https://file.aiquickdraw.com/mathbot/file/17292838860674fs627zy.jpg

The given expression is for calculating the pressure (Pm) exerted by a column of fluid, which can be determined using the hydrostatic pressure formula:

\[
P_m = (\rho) (g) (h)
\]

Where:
- \(\rho\) = density of the fluid (in kg/m\(^3\))
- \(g\) = acceleration due to gravity (in m/s\(^2\))
- \(h\) = height of the fluid column (in meters)

From the provided image:
- \(\rho = 13,600 \, \text{kg/m}^3\)
- \(g = 9.81 \, \text{m/s}^2\)
- \(h = 0.60 \, \text{m}\)

Now, substituting the values into the formula:

\[
P_m = (13,600 \, \text{kg/m}^3) \times (9.81 \, \text{m/s}^2) \times (0.60 \, \text{m})
\]

Calculating this:

\[
P_m = 13,600 \times 9.81 \times 0.60
\]
\[
P_m = 80,068.8 \, \text{Pa} \, (\text{Pascal})
\]

So, the pressure \(P_m\) is approximately \(80,068.8\) Pascals or \(80.07 \, \text{kPa}\).

Would you like further details or have any questions?

Here are 5 related questions to explore further:
1. What is the physical meaning of hydrostatic pressure?
2. How does changing the fluid density affect the pressure calculation?
3. Why is gravity (\(g\)) used in the calculation of pressure?
4. How would the pressure change if the height of the fluid column increased?
5. What are other applications of the hydrostatic pressure formula?

**Tip**: Always ensure that all units are consistent when performing calculations, as mixing units can lead to errors in the final result.

Calculate the pressure exerted by a column of fluid using the given values: density = 13,600 kg/m^3, gravity = 9.81 m/s^2, and height = 0.60 m.

Learn how to calculate the pressure exerted by a fluid column with a density of 13,600 kg/m^3, a gravity constant of 9.81 m/s^2, and a height of 0.60 meters. Detailed step-by-step solution included. Suitable for students in Grades 9-12.

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