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To solve the problem of how much more coal was used in 1990 than in 2000, we need to calculate the difference between the two values given in the table.

From the table:
- Coal used in 1990: \( 1.08 \times 10^8 \, \text{tonnes} \)
- Coal used in 2000: \( 5.99 \times 10^7 \, \text{tonnes} \)

### Step 1: Express both quantities in the same exponent form
The coal used in 2000 can be rewritten as:

\[
5.99 \times 10^7 = 0.599 \times 10^8
\]

### Step 2: Subtract the coal usage
Now, subtract the 2000 amount from the 1990 amount:

\[
1.08 \times 10^8 - 0.599 \times 10^8 = (1.08 - 0.599) \times 10^8
\]

\[
= 0.481 \times 10^8
\]

### Step 3: Write the result in standard form
This can be expressed in standard form as:

\[
4.81 \times 10^7
\]

Thus, **4.81 × 10^7 tonnes** more coal was used in 1990 than in 2000.

Let me know if you want further details on any part of this solution. Here are 5 related questions to extend your understanding:

1. How do you convert between different powers of ten when comparing quantities in standard form?
2. What is standard form and why is it useful in representing very large or very small numbers?
3. How do you handle addition and subtraction when numbers are given in standard form?
4. How would the result change if the values were given with different exponents (e.g., \(10^6\) instead of \(10^7\))?
5. What are some other practical applications of using standard form in real-world problems?

**Tip:** When subtracting or adding numbers in standard form, make sure the exponents are the same before proceeding with the operation!

How much more coal was used in 1990 than in 2000? Write the amount of coal used in standard form.

Learn how to calculate how much more coal was used in 1990 compared to 2000 using scientific notation. This problem involves subtracting numbers in standard form and writing the final result as 4.81 × 10^7 tonnes.

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