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To solve this problem, we need to find out how much of Sierra's lawn she can cover with the grass seed she has.

### Problem Breakdown:
- **Total seed needed for full lawn**: \(\frac{5}{6}\) lbs
- **Seed Sierra has**: \(\frac{1}{3}\) lbs

We need to find out what fraction of the lawn she can cover, which is calculated by the ratio:

\[
\text{Fraction of lawn covered} = \frac{\text{Seed she has}}{\text{Total seed needed}} = \frac{\frac{1}{3}}{\frac{5}{6}}
\]

### Step-by-Step Solution:

1. **Dividing fractions**: Dividing by a fraction is the same as multiplying by its reciprocal. Therefore, we have:

\[
\frac{\frac{1}{3}}{\frac{5}{6}} = \frac{1}{3} \times \frac{6}{5}
\]

2. **Simplifying**: Multiply the numerators together and the denominators together:

\[
\frac{1 \times 6}{3 \times 5} = \frac{6}{15}
\]

3. **Reducing the fraction**: Simplify \(\frac{6}{15}\) by dividing both the numerator and the denominator by their greatest common divisor, which is 3:

\[
\frac{6 \div 3}{15 \div 3} = \frac{2}{5}
\]

So, Sierra can cover \(\frac{2}{5}\) of her lawn.

### Final Answer:
Sierra can cover \(\frac{2}{5}\) of her lawn with the grass seed she currently has.

Would you like more details or have any other questions? Here are some related questions:

1. What is the meaning of the reciprocal of a fraction?
2. How do you find the greatest common divisor of two numbers?
3. How can you check if two fractions are equivalent?
4. What other method can be used to solve this problem besides dividing fractions?
5. How can you convert \(\frac{2}{5}\) to a decimal?

**Tip:** Always simplify your final answer to its lowest terms to make it easier to understand.

Sierra spreads grass seed on her lawn. She needs 5/6 lb of grass seed to cover her whole lawn. She has 1/3 lb of grass seed. How much of her lawn can she cover?

Find out how much of Sierra's lawn she can cover with 1/3 lb of grass seed when 5/6 lb is needed for the full lawn. This problem involves dividing and simplifying fractions, and is suitable for students in Grades 5-6.

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