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Let's solve this step-by-step.

1. **Cost per kilogram:**
   - Salmon costs $22 per kg.
   - Mackerel costs $10 per kg.

2. **Quantity purchased:**
   - Mrs. Wong buys $1 \frac{1}{2}$ kg of salmon and $2 \frac{1}{5}$ kg of mackerel.
   - Converting these to improper fractions:
     - $1 \frac{1}{2} = \frac{3}{2}$ kg of salmon
     - $2 \frac{1}{5} = \frac{11}{5}$ kg of mackerel

3. **Total cost calculation:**
   - For salmon:
     \[
     \frac{3}{2} \times 22 = \frac{3 \times 22}{2} = \frac{66}{2} = 33 \text{ dollars}
     \]
   - For mackerel:
     \[
     \frac{11}{5} \times 10 = \frac{11 \times 10}{5} = \frac{110}{5} = 22 \text{ dollars}
     \]

4. **Total amount Mrs. Wong has to pay:**
   \[
   33 + 22 = 55 \text{ dollars}
   \]

So, Mrs. Wong has to pay **$55**.

Would you like further details or have questions?

Here are some related questions you could explore:
1. What would the cost be if Mrs. Wong bought twice as much fish?
2. If salmon's price was reduced by 10%, how much would Mrs. Wong save?
3. How much would Mrs. Wong pay if she only bought salmon?
4. What is the cost difference if salmon and mackerel prices were switched?
5. How would the cost change if she bought 3 kg of each fish?

**Tip:** Converting mixed fractions to improper fractions helps simplify calculations, especially with unit pricing.

At a market, 1 kg of salmon costs $22 and 1 kg of mackerel costs $10. Mrs. Wong buys 1/2 kg of salmon and 2/5 kg of mackerel. How much does Mrs. Wong have to pay?

This problem explains how to calculate the total cost when Mrs. Wong buys 1/2 kg of salmon at $22/kg and 2/5 kg of mackerel at $10/kg, using fraction multiplication and addition. Suitable for students in Grades 5-6.

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