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The problem asks how many motors the fuses can carry when the circuit is fused for a 25-horsepower motor but the motor is being replaced by several 5-horsepower motors.

### Step-by-Step Solution:
1. **Total Power Capacity:** The circuit is fused for a 25-horsepower motor.
2. **Power of Each New Motor:** Each new motor is 5 horsepower.
3. **How Many Motors:** To find how many 5-horsepower motors the fuse can handle, divide the total horsepower by the horsepower of one motor:
   \[
   \text{Number of motors} = \frac{\text{Total horsepower}}{\text{Horsepower per motor}} = \frac{25}{5} = 5
   \]

Therefore, the fuses can carry **5 motors**.

Would you like more details or have any questions about this?

Here are 5 related questions to consider:
1. What is the relation between power, current, and voltage in an electrical circuit?
2. How does the horsepower rating of a motor relate to its electrical consumption?
3. If the fuse were rated for 30 hp, how many 5-hp motors could it carry?
4. What happens if you exceed the fuse rating with too many motors?
5. How do you calculate the efficiency of a motor in terms of power input and output?

**Tip:** Always ensure that electrical components, like fuses, are rated properly to avoid overloads that could lead to equipment damage or hazards.

A certain circuit is properly fused for a 25-horsepower motor. If the motor is to be replaced by several 5-hp motors, how many motors will the fuses be able to carry?

Find out how many 5-horsepower motors can be connected to a circuit fused for a 25-horsepower motor. This step-by-step problem covers the basic division of power capacities, ideal for students in Grades 6-8.

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