There is 3 and 3/4 of a pizza leftover from the night before.  How many 1 and 1/8 portions are there?

enter your answer as an improper fraction (make sure your answer is in simplest form)  

enter your answer as a mixed number  

Blank

Let's solve this step-by-step:

1. **Convert the amounts to improper fractions:**  
   - \(3 \frac{3}{4}\) becomes:
     \[
     3 \frac{3}{4} = \frac{4 \times 3 + 3}{4} = \frac{15}{4}
     \]
   - \(1 \frac{1}{8}\) becomes:
     \[
     1 \frac{1}{8} = \frac{8 \times 1 + 1}{8} = \frac{9}{8}
     \]

2. **Set up the division:**  
   To find how many portions of \(1 \frac{1}{8}\) are in \(3 \frac{3}{4}\), divide \( \frac{15}{4} \) by \( \frac{9}{8} \).  
   \[
   \frac{15}{4} \div \frac{9}{8} = \frac{15}{4} \times \frac{8}{9}
   \]

3. **Simplify the multiplication:**  
   Multiply the numerators and denominators:
   \[
   \frac{15 \times 8}{4 \times 9} = \frac{120}{36}
   \]
   Now simplify the fraction:
   \[
   \frac{120}{36} = \frac{10}{3}
   \]

4. **Convert to a mixed number:**  
   \(\frac{10}{3} = 3 \frac{1}{3}\).

---

### Final Answers:
- **Improper fraction:** \(\frac{10}{3}\)  
- **Mixed number:** \(3 \frac{1}{3}\)

---

Do you have any questions or need further details?  

Here are 5 related questions to explore:  
1. How do you convert a mixed number to an improper fraction?  
2. How do you perform division with fractions?  
3. What is the least common denominator, and when is it used?  
4. How do you convert improper fractions back into mixed numbers?  
5. Can you find the decimal value of \(3 \frac{1}{3}\)?  

**Tip:** When dividing fractions, remember to multiply by the reciprocal of the second fraction.

There is 3 and 3/4 of a pizza leftover from the night before. How many 1 and 1/8 portions are there? Enter your answer as an improper fraction (make sure your answer is in simplest form) and as a mixed number.

Find out how to calculate how many 1 and 1/8 portions fit into 3 and 3/4 pizza using fraction division. This guide includes converting mixed numbers to improper fractions, multiplying by reciprocals, and simplifying the final result. Suitable for students in Grades 6-8.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation