Math Problem Statement
Solution
Let's solve the questions one by one.
Question 1
Agung rolls a die 1,200 times, and the frequency of each outcome is recorded in the table:
- Frequency for each side:
- 1: 180
- 2: 240
- 3: 195
- 4: 195
- 5: 180
- 6: 210
The relative frequency of getting a 1 is calculated as:
So, the answer is B. .
Question 2
There are 10 pieces of paper numbered 1 to 10. If 2 are drawn randomly and their numbers are added, the probability of getting an odd sum is calculated as:
- Total ways to choose 2 pieces: .
- Ways to get an odd sum:
- Choose 1 even number and 1 odd number.
- There are 5 odd numbers and 5 even numbers.
- Combinations: .
Probability:
So, the answer is E. .
Question 3
Pak Karno has a box with 60 fruits: 8 pears, 12 avocados, and the rest are guavas. The probability of drawing a guava:
- Number of guavas: .
- Probability:
So, the answer is C. .
Question 4
The diagram shows a spinner divided into 8 equal parts, numbered 1 to 8. The probability of the arrow pointing to a number greater than 5 (i.e., 6, 7, or 8):
- There are 3 favorable outcomes.
- Probability:
So, the answer is C. .
Question 5
The word "KALIMANTAN" has 10 letters, and the frequency of the letter "A" is 3. The probability of choosing an "A":
So, the answer is C. .
Let me know if you'd like to delve into any question further. Here are five related questions to expand on this:
- What is the expected value of rolling a weighted die given different probabilities?
- How do you find the probability of getting a sum divisible by 3 when drawing two cards numbered 1 to 10?
- If Pak Karno adds 10 more guavas to his collection, what is the new probability of selecting a guava?
- What is the probability of landing on an odd number on the given spinner?
- How would the probability change if the word was "MALAYSIA" instead of "KALIMANTAN"?
Tip: For probability questions involving "at least one" events, it is often easier to calculate the complement probability (i.e., "none") first and then subtract from 1.
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Math Problem Analysis
Mathematical Concepts
Probability
Combinatorics
Relative Frequency
Formulas
P(A) = favorable outcomes / total outcomes
Relative Frequency = frequency / total trials
Combinations: C(n, k) = n! / [k!(n-k)!]
Theorems
Basic Probability Theorem
Combination Formula
Suitable Grade Level
High School (Grades 10-12)
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