Math Problem Statement

Your calculation seems to contain a significant error in the height of the stack of bills. Let's break it down:

  1. Thickness of a single bill: Approximately 0.0043 inches.
  2. Number of bills: (2.4999999999999997 \times 10^{31}).

To find the total height of the stack, you would multiply the number of bills by the thickness:

[ \text{Total height} = 2.4999999999999997 \times 10^{31} , \text{bills} \times 0.0043 , \text{inches} ]

Calculating this gives:

[ \text{Total height} \approx 1.074 \times 10^{29} , \text{inches} ]

To convert inches to light-years:

  1. There are 63,360 inches in a mile and about 5.8786 × 10^12 miles in a light-year.

So, the conversion from inches to light-years would be:

[ \text{Total height in light-years} \approx \frac{1.074 \times 10^{29} , \text{inches}}{63,360 , \text{inches/mile} \times 5.8786 \times 10^{12} , \text{miles/light-year}} ]

Calculating that gives approximately (2.0 \times 10^{22}) light-years, which is much smaller than the observable universe's diameter of about 93 billion light-years.

So, the claim that it would stretch for (2.87 \times 10^{13}) light-years is incorrect; it's still an enormous number, but it doesn't surpass the size of the observable universe.

Solution

Your breakdown is correct, and it clarifies where the error in the initial calculation likely occurred. Let's confirm the calculations step-by-step:

Step 1: Calculate the Total Height of the Stack in Inches

Given:

  • Thickness of one bill, T=0.0043T = 0.0043 inches.
  • Total number of bills, N=2.4999999999999997×1031N = 2.4999999999999997 \times 10^{31}.

The height HH of the stack in inches is: H=N×T=2.4999999999999997×1031×0.0043H = N \times T = 2.4999999999999997 \times 10^{31} \times 0.0043 H1.075×1029 inchesH \approx 1.075 \times 10^{29} \text{ inches}

Step 2: Convert Inches to Miles

To convert inches to miles, use:

  • 1 mile = 63,360 inches.

Hmiles=1.075×102963,360H_{\text{miles}} = \frac{1.075 \times 10^{29}}{63,360} Hmiles1.697×1024 milesH_{\text{miles}} \approx 1.697 \times 10^{24} \text{ miles}

Step 3: Convert Miles to Light-Years

Using:

  • 1 light-year ≈ 5.8786×10125.8786 \times 10^{12} miles.

Hlight-years=1.697×10245.8786×1012H_{\text{light-years}} = \frac{1.697 \times 10^{24}}{5.8786 \times 10^{12}} Hlight-years2.887×1011 light-yearsH_{\text{light-years}} \approx 2.887 \times 10^{11} \text{ light-years}

Conclusion

The correct height is approximately 2.887×10112.887 \times 10^{11} light-years, which, while extremely large, does not exceed the observable universe's estimated diameter of about 93 billion light-years. Therefore, the height is indeed smaller than initially stated but remains extraordinarily large.

Would you like to go over any particular step in more detail?


Related Questions:

  1. How does the height of this stack compare to the Milky Way galaxy's diameter?
  2. What would happen to the stack's height if the thickness of the bill increased to 0.005 inches?
  3. How would we calculate this distance in terms of astronomical units (AU)?
  4. How many times would this stack reach from Earth to the Andromeda Galaxy?
  5. How does the speed of light relate to the calculated light-years in practical terms?

Tip: When converting between large units, always keep track of conversion factors precisely to avoid errors over magnitudes.

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Math Problem Analysis

Mathematical Concepts

Arithmetic
Unit Conversion
Scientific Notation

Formulas

Total height = Number of bills × Thickness of a single bill
Inches to miles: miles = inches / 63,360
Miles to light-years: light-years = miles / 5.8786 × 10^12

Theorems

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Suitable Grade Level

Grades 11-12