To determine the height of the diving platform, we can analyze the vertical motion of Janet as she falls under the influence of gravity. Since she jumps horizontally, her initial vertical velocity is zero, and only gravity affects her vertical descent.

Step-by-Step Solution

1. Given values:

   • Time to fall, $t = 1.1$ s
   • Acceleration due to gravity, $g = 9.8 \, \text{m/s}^2$

2. Formula for vertical displacement: Since her initial vertical velocity is zero, we use the equation: $h = \frac{1}{2} g t^2$

3. Substitute the values: $h = \frac{1}{2} \times 9.8 \, \text{m/s}^2 \times (1.1 \, \text{s})^2$

4. Calculate the height: $h = \frac{1}{2} \times 9.8 \times 1.21$ $h = 4.9 \times 1.21$ $h \approx 5.929 \, \text{m}$

So, the height of the platform is approximately 5.93 meters.

Would you like further details, or do you have any questions?

Here are some related questions to expand on this concept:

1. How would Janet’s landing time change if she jumped off with a higher horizontal velocity?
2. What is the horizontal distance Janet traveled before hitting the water?
3. How would the height of the platform change if gravity on another planet were different?
4. How does the initial horizontal velocity affect the vertical displacement?
5. What would happen if Janet’s initial vertical velocity were not zero?

Tip: Remember that in projectile motion, horizontal and vertical motions are analyzed separately, with gravity only affecting the vertical motion.