Math Problem Statement

If a local gym charges a membership fee of 50$ plus an additional 10$ per class attended, how can we represent the total cost C as a function of the number classes x attended?

what is the maximum number of classes you could attend in a month if your budget is 200$

Solution

We can represent the total cost CC as a function of the number of classes xx attended as follows:

C(x)=50+10xC(x) = 50 + 10x

  • The term 5050 represents the fixed membership fee.
  • The term 10x10x represents the cost for attending xx classes, where each class costs 10 dollars.

Now, to find the maximum number of classes you can attend given a budget of 200 dollars, we can set C(x)200C(x) \leq 200 and solve for xx:

50+10x20050 + 10x \leq 200

Subtract 50 from both sides:

10x15010x \leq 150

Now divide by 10:

x15x \leq 15

Thus, the maximum number of classes you can attend is 15.

Would you like further details or have any questions?

Here are 5 related questions:

  1. How would the function change if the membership fee increased to $60?
  2. What would the function look like if there was also a discount of $5 after attending 10 classes?
  3. How would you solve for xx if your budget was $250?
  4. What if the class price increased to $15 per class, how many classes could you afford?
  5. What if the gym offered a one-time discount of $20, how many classes could you attend?

Tip: When working with linear functions, always identify fixed and variable components to set up your equation efficiently.

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Inequalities

Formulas

C(x) = 50 + 10x

Theorems

Linear inequality solving

Suitable Grade Level

Grades 6-8