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The problem asks for the greatest number of Halloween bags that can be made by distributing 27 Snickers and 36 Milky Way bars evenly, ensuring each bag gets an equal number of both types of candy.

To solve this, we need to find the **greatest common divisor (GCD)** of 27 and 36, because the greatest number of bags is determined by the largest number that can divide both 27 and 36 evenly.

Let's calculate the GCD of 27 and 36:

- The divisors of 27 are: 1, 3, 9, 27
- The divisors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, 36

The greatest common divisor is **9**.

Therefore, the greatest number of bags that can be made is **9**.

Each bag will contain:
- \( \frac{27}{9} = 3 \) Snickers
- \( \frac{36}{9} = 4 \) Milky Way bars

Would you like further details on the GCD method or have any questions?

Here are 5 related questions to expand on this concept:
1. What if the student had 30 Snickers and 45 Milky Way bars? How many bags could be made?
2. How would the answer change if there were 28 Snickers and 36 Milky Way bars?
3. What is the least number of bags that can be made if both candies must be divided equally?
4. How can prime factorization help in finding the GCD?
5. What is the significance of the GCD in dividing things evenly?

**Tip:** The GCD is useful not only in mathematics but also in real-life scenarios where you need to divide things into equal parts.

A student has 27 Snickers and 36 Milky Way bars. He puts an equal number of each type of candy in Halloween bags. What is the greatest number of bags that can be made?

Learn how to find the greatest number of Halloween bags that can be made with 27 Snickers and 36 Milky Way bars. This problem involves finding the greatest common divisor (GCD) of two numbers and dividing candies equally. Suitable for Grades 5-7.

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