Math Problem Statement

A function is shown in the table below. On which interval of x is the average rate of change of the function the greatest?

Solution

To determine on which interval the average rate of change of the function is the greatest, we need to calculate the average rate of change for each interval provided in the table. The average rate of change of a function over an interval [x1,x2][x_1, x_2] is given by the formula:

Average Rate of Change=y2y1x2x1\text{Average Rate of Change} = \frac{y_2 - y_1}{x_2 - x_1}

Let's compute this for each interval in the table.

  1. Interval [0,3][0, 3]: 15430=1133.67\frac{15 - 4}{3 - 0} = \frac{11}{3} \approx 3.67

  2. Interval [3,12][3, 12]: 2015123=590.56\frac{20 - 15}{12 - 3} = \frac{5}{9} \approx 0.56

  3. Interval [12,20][12, 20]: 27202012=78=0.875\frac{27 - 20}{20 - 12} = \frac{7}{8} = 0.875

  4. Interval [20,24][20, 24]: 40272420=134=3.25\frac{40 - 27}{24 - 20} = \frac{13}{4} = 3.25

Comparing the calculated rates of change:

  • Interval [0,3][0, 3]: 3.67
  • Interval [3,12][3, 12]: 0.56
  • Interval [12,20][12, 20]: 0.875
  • Interval [20,24][20, 24]: 3.25

The greatest average rate of change occurs on the interval [0,3][0, 3] with a rate of approximately 3.67.

Would you like more details or have any questions about this? Here are some related questions:

  1. How do you calculate the average rate of change for a nonlinear function?
  2. What does the average rate of change tell us about a function's behavior?
  3. How is the average rate of change related to the slope of a linear function?
  4. How can we estimate the instantaneous rate of change from a table of values?
  5. Can the average rate of change be negative, and what does it signify?

Tip: For linear functions, the average rate of change is constant over any interval, but for nonlinear functions, it can vary widely depending on the chosen interval.

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Math Problem Analysis

Mathematical Concepts

Functions
Average Rate of Change

Formulas

Average Rate of Change = (y2 - y1) / (x2 - x1)

Theorems

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Suitable Grade Level

Grades 9-12