Math Problem Statement

Sketch the graph of y = x², y = 2x², and y = ½x² on the same set of axes

Solution

To sketch the graphs of the given equations y=x2y = x^2, y=2x2y = 2x^2, and y=12x2y = \frac{1}{2}x^2 on the same axes, follow these steps:

Steps to sketch:

  1. Start with the basic parabola: y=x2y = x^2

    • This is a standard parabola with the vertex at the origin (0, 0).
    • The graph opens upwards and is symmetric about the y-axis.
    • As xx moves away from 0, y=x2y = x^2 grows quadratically.
  2. Next, sketch y=2x2y = 2x^2

    • This is also a parabola opening upwards, but it's "narrower" than y=x2y = x^2 because the coefficient 2 makes the graph stretch more steeply.
    • It has the same vertex at (0, 0), but for any given xx, y=2x2y = 2x^2 will be twice as large as y=x2y = x^2.
  3. Finally, sketch y=12x2y = \frac{1}{2}x^2

    • This is also a parabola opening upwards, but it is "wider" than y=x2y = x^2 because the coefficient 12\frac{1}{2} makes the graph grow slower.
    • The vertex is at (0, 0), and for any given xx, y=12x2y = \frac{1}{2}x^2 will be half as large as y=x2y = x^2.

Key differences between the graphs:

  • ( y = 2x^2 \

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Math Problem Analysis

Mathematical Concepts

Quadratic Functions
Graphing Parabolas
Transformations of Functions

Formulas

Standard form of a quadratic function: y = ax²

Theorems

Properties of Parabolas
Vertical Stretch and Compression

Suitable Grade Level

Grades 8-10