Let's graph the function given the table of values. The function provided, which appears to be $y = x^2 + 3$, has the corresponding table of values:

Table of Values:

$x$	$y$
-10	103
-9	84
-8	67
-7	52
-6	39
-5	28
-4	19
-3	12
-2	7
-1	4
0	3
1	4
2	7
3	12
4	19
5	28
6	39
7	52
8	67
9	84
10	103

To plot at least five points from this table, you can select five values of $(x, y)$. Here are some recommended points to plot:

1. $(-5, 28)$
2. $(-3, 12)$
3. $(0, 3)$
4. $(3, 12)$
5. $(5, 28)$

Plotting the Points:

1. Start by marking the x-axis and y-axis on the graph.
2. Plot the points $(-5, 28)$, $(-3, 12)$, $(0, 3)$, $(3, 12)$, and $(5, 28)$ on the graph.
3. Connect these points smoothly to form the parabolic shape of the function $y = x^2 + 3$.

Graph Characteristics:

• The graph is a parabola opening upwards, shifted 3 units up from the standard position of $y = x^2$.

Would you like a detailed graph of this function, or do you have any specific questions about plotting these points?

Follow-Up Questions:

1. What happens to the graph if you change the constant value in the function?
2. How would the graph look if the function were $y = -x^2 + 3$?
3. What is the vertex of the parabola represented by this function?
4. How does changing the coefficient of $x^2$ affect the width of the parabola?
5. How can you determine the symmetry of the graph based on its function?

Tip:

To quickly identify key points on a parabola, always start with the vertex and symmetry points around it!