Math Problem Statement

Draw graphs of the following functions: f(x) = -x^2 + 2x - 1, y = |x| + x, |x| = |y|, y^2 = x

Solution

The image contains four functions for which you are asked to draw the graphs. They are:

  1. f(x)=x2+2x1f(x) = -x^2 + 2x - 1
  2. y=x+xy = |x| + x
  3. x=y|x| = |y|
  4. y2=xy^2 = x

Let’s briefly discuss each of these functions and how their graphs look:

  1. f(x)=x2+2x1f(x) = -x^2 + 2x - 1:
    This is a quadratic function in the form ax2+bx+cax^2 + bx + c, with a=1a = -1, b=2b = 2, and c=1c = -1. It represents a downward-opening parabola. We can find the vertex using the formula x=b2ax = -\frac{b}{2a} and then plot the points accordingly.

  2. y=x+xy = |x| + x:
    This function involves the absolute value of xx, which behaves differently for positive and negative values of xx. For x0x \geq 0, y=2xy = 2x, and for x<0x < 0, y=0y = 0.

  3. x=y|x| = |y|:
    This represents a symmetrical graph with respect to both the x-axis

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Math Problem Analysis

Mathematical Concepts

Quadratic Functions
Absolute Value Functions
Symmetry in Graphs
Parabolas

Formulas

Quadratic equation: f(x) = ax^2 + bx + c
Absolute value: y = |x|
Symmetry: |x| = |y|
Parabola: y^2 = x

Theorems

Vertex form of a quadratic function
Properties of absolute value
Parabolas and conic sections

Suitable Grade Level

Grades 9-12