Math Problem Statement

Use technology to find points and then graph the function y, equals, left parenthesis, x, minus, 1, right parenthesis, squared, commay=(x−1)2, following the instructions below. how do I solve this without a calculator

Solution

To solve this without a calculator, let's approach it step-by-step. The function given is:

y=(x1)2y = (x - 1)^2

This is a basic quadratic function in the form of y=(xh)2+ky = (x - h)^2 + k, which represents a parabola that opens upwards. Here, h=1h = 1 and k=0k = 0, so the parabola is shifted 1 unit to the right along the x-axis and has its vertex at (1,0)(1, 0).

Step 1: Identify Key Points

  1. Vertex: The vertex is the point where the parabola changes direction. Since h=1h = 1 and k=0k = 0, the vertex of this function is at: (1,0)(1, 0)

  2. Axis of Symmetry: The axis of symmetry for this parabola is the vertical line that passes through the vertex. For our function, this line is: x=1x = 1

  3. Other Points: To graph this without a calculator, choose values of xx around the vertex to find corresponding yy-values.

    Let's plug in some values for xx near 1:

    • For x=0x = 0: y=(01)2=1y = (0 - 1)^2 = 1 So, the point is (0,1)(0, 1).

    • For x=2x = 2: y=(21)2=1y = (2 - 1)^2 = 1 So, the point is (2,1)(2, 1).

    • For x=1x = -1: y=(11)2=4y = (-1 - 1)^2 = 4 So, the point is (1,4)(-1, 4).

    • For x=3x = 3: y=(31)2=4y = (3 - 1)^2 = 4 So, the point is (3,4)(3, 4).

    Now we have a set of points: (1,0)(1, 0), (0,1)(0, 1), (2,1)(2, 1), (1,4)(-1, 4), and (3,4)(3, 4).

Step 2: Plot the Points and Draw the Parabola

  1. Start by plotting the vertex (1,0)(1, 0) on the graph.
  2. Then, plot the points we calculated: (0,1)(0, 1), (2,1)(2, 1), (1,4)(-1, 4), and (3,4)(3, 4).
  3. Since this is a parabola, connect these points with a smooth curve opening upwards.

Summary of Steps

  • Identify the vertex at (1,0)(1, 0).
  • Plot points around the vertex.
  • Draw the parabola through these points.

Would you like more detailed information on plotting these points or understanding the transformations? Here are some follow-up questions you might find helpful:

  1. How does shifting the vertex affect the graph of a parabola?
  2. What is the significance of the axis of symmetry in a parabola?
  3. How would the graph change if the function were y=(x1)2y = -(x - 1)^2?
  4. Why is y=x2y = x^2 the parent function for all quadratic equations?
  5. How do you determine if a parabola opens upward or downward?

Tip: To check your points, substitute values into the equation step-by-step to verify accuracy.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions
Graphing Parabolas

Formulas

y = (x - h)^2 + k

Theorems

Vertex form of a quadratic function
Symmetry of parabolas

Suitable Grade Level

Grades 7-9