Math Problem Statement

Linear Inequality Graph 2-Variables

Question 1 Which inequality is shown on the graph? Responses A y < 4x + 5y < 4x + 5 B y < −4xy < −4x C y < −4x + 5y < −4x + 5 D y < −x + 5y < − 1 4 x + 5

Question 2 Which ordered pair is NOT a solution to the inequality? Responses A (1, 1)(1, 1) B (0, 2)(0, 2) C (1, −2)(1, −2) D (−2, −2)(−2, −2)

Solution

Question 1: Which inequality is shown on the graph?

To determine the inequality, we need to consider two aspects:

  1. Slope of the line: The slope (mm) can be identified based on how steep the line is. The given options have slopes like 4-4, 14-\frac{1}{4}, and 44, so the graph must show whether it's steep or relatively flat.

  2. Y-intercept: This is the point where the line crosses the y-axis. It's given in the options as +5+5 in some of the choices.

The line must also show whether the inequality uses a strict inequality ("<" or ">") or includes the boundary ("≤" or "≥"). If the line is dashed, it represents strict inequalities ("<" or ">"). If the line is solid, it represents inclusive inequalities ("≤" or "≥").

Assuming you are asking about a specific inequality related to this graph:

  • If the line has a negative slope and crosses the y-axis at +5, then the inequality might look like y<4x+5y < -4x + 5 or y<14x+5y < -\frac{1}{4}x + 5.

  • If the shading is below the line, the inequality would use "<" (less than). If the shading is above the line, the inequality would use ">".

Given the choices, Option C y<4x+5y < -4x + 5 seems likely if the line has a negative slope and crosses the y-axis at 5, with shading below the line.

Question 2: Which ordered pair is NOT a solution to the inequality?

For this, plug in the given ordered pairs into the inequality from Question 1, assuming the inequality is y<4x+5y < -4x + 5.

Checking the pairs:

  1. (1, 1): y=1andx=1y = 1 \quad \text{and} \quad x = 1 Plug into y<4x+5y < -4x + 5: 1<4(1)+51<4+51<1(False because 11)1 < -4(1) + 5 \quad \Rightarrow \quad 1 < -4 + 5 \quad \Rightarrow \quad 1 < 1 \quad (\text{False} \ because \ 1 \not< 1) So, (1, 1) is NOT a solution.

  2. (0, 2): y=2andx=0y = 2 \quad \text{and} \quad x = 0 Plug into y<4x+5y < -4x + 5: 2<4(0)+52<5(True)2 < -4(0) + 5 \quad \Rightarrow \quad 2 < 5 \quad (\text{True}) So, (0, 2) is a solution.

  3. (1, -2): y=2andx=1y = -2 \quad \text{and} \quad x = 1 Plug into y<4x+5y < -4x + 5: 2<4(1)+52<4+52<1(True)-2 < -4(1) + 5 \quad \Rightarrow \quad -2 < -4 + 5 \quad \Rightarrow \quad -2 < 1 \quad (\text{True}) So, (1, -2) is a solution.

  4. (-2, -2): y=2andx=2y = -2 \quad \text{and} \quad x = -2 Plug into y<4x+5y < -4x + 5: 2<4(2)+52<8+52<13(True)-2 < -4(-2) + 5 \quad \Rightarrow \quad -2 < 8 + 5 \quad \Rightarrow \quad -2 < 13 \quad (\text{True}) So, (-2, -2) is a solution.

Thus, the ordered pair (1, 1) is NOT a solution, and the correct answer for Question 2 is A.


Relative Questions:

  1. How do you determine the slope of a line from a graph?
  2. How does shading on a graph help identify the inequality?
  3. What is the significance of the y-intercept in linear equations?
  4. Why are dashed lines used for strict inequalities?
  5. How can we verify if an ordered pair is a solution to a given inequality?

Tip:

Always check the direction of shading on the graph to identify whether the inequality uses "<" (shading below the line) or ">" (shading above the line).

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Math Problem Analysis

Mathematical Concepts

Linear Inequalities
Graphing
Slope-Intercept Form

Formulas

y = mx + b (Slope-Intercept Form)

Theorems

Linear Inequality Theorem
Slope and Intercept Theorem

Suitable Grade Level

Grades 8-10