Make a graph of 2x+3y>-6 and y<=4x+8 combined 

Here is the combined graph of the inequalities:

1. \( 2x + 3y > -6 \): The boundary line is dashed, with the shaded blue region above it representing the solution area.
2. \( y \leq 4x + 8 \): The boundary line is solid, with the shaded green region below it representing the solution area.

The overlapping region, where both inequalities hold, is where the shaded areas overlap.

Would you like further details or clarifications?

Here are 5 related questions to explore further:

1. What is the region of overlap between the two inequalities?
2. How do you solve the system of inequalities algebraically?
3. What happens if one of the inequalities is strict and the other is non-strict?
4. Can you graph inequalities with quadratic terms?
5. How do we find the intersection point of two linear inequalities?

**Tip:** When graphing inequalities, always pay attention to whether the inequality is strict ("<" or ">") or non-strict ("≤" or "≥") as it determines whether the boundary line is dashed or solid.

Make a graph of 2x + 3y > -6 and y <= 4x + 8 combined

This guide shows how to graph the combined inequalities 2x + 3y > -6 and y ≤ 4x + 8. The solution includes step-by-step instructions on how to plot the boundary lines, determine the regions of interest, and find the overlapping solution area. Suitable for students in Grades 9-10.

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