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The equation you're working with is \( y = x + 5 \). Let's solve for both the \( x \)-intercept and \( y \)-intercept.

### 1. **Finding the \( x \)-Intercept:**
The \( x \)-intercept occurs when \( y = 0 \). Set \( y \) to 0 in the equation and solve for \( x \):

\[
0 = x + 5
\]
\[
x = -5
\]

Thus, the \( x \)-intercept is \( (-5, 0) \).

### 2. **Finding the \( y \)-Intercept:**
The \( y \)-intercept occurs when \( x = 0 \). Set \( x \) to 0 in the equation and solve for \( y \):

\[
y = 0 + 5 = 5
\]

Thus, the \( y \)-intercept is \( (0, 5) \).

### Coordinates:
- **\( x \)-intercept**: \( (-5, 0) \)
- **\( y \)-intercept**: \( (0, 5) \)

Now you can plot these points on the graph, draw a straight line through them, and you'll have your line.

Let me know if you would like further clarification or help plotting the graph!

### Follow-up questions:
1. What happens if we change the slope in the equation to something other than 1?
2. How do you interpret a negative slope graphically?
3. What if there is no \( y \)-intercept? What would the equation look like?
4. Can a line have both \( x \)- and \( y \)-intercepts as 0?
5. How does the graph change if we add a constant term to both sides?

### Tip:
When graphing, always start by plotting the intercepts first—they provide easy and accurate reference points for the rest of the graph.

Use the intercepts to graph the equation y = x + 5. Find the x-intercept and y-intercept.

This problem involves finding the x- and y-intercepts for the linear equation y = x + 5. Learn how to use simple algebraic methods to graph the line and identify intercept points. This problem is appropriate for students in Grades 8-10 studying linear equations.

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