The image shows a math problem asking to graph the equation $y = \frac{1}{4}x + 5$, with a domain of $D: [-8, -4, 0, 4]$.

Let's break this down:

1. Equation of the line: $y = \frac{1}{4}x + 5$ is a linear equation with a slope of $\frac{1}{4}$ and a y-intercept of 5. This means the line rises by 1 unit for every 4 units it moves to the right.

2. Given domain: $D: [-8, -4, 0, 4]$ means you are asked to graph the line for the x-values: $-8, -4, 0, 4$.

3. To find the points on the graph:

   • When $x = -8$: $y = \frac{1}{4}(-8) + 5 = -2 + 5 = 3$
   • When $x = -4$: $y = \frac{1}{4}(-4) + 5 = -1 + 5 = 4$
   • When $x = 0$: $y = \frac{1}{4}(0) + 5 = 5$
   • When $x = 4$: $y = \frac{1}{4}(4) + 5 = 1 + 5 = 6$

4. Plotting points:

   • $(-8, 3)$
   • $(-4, 4)$
   • $(0, 5)$
   • $(4, 6)$

5. Graph: Now, these points would form a line when plotted on the grid.

Would you like me to explain the graphing process further or have any questions?

Here are 5 related questions to deepen your understanding:

1. What is the slope of a line and how does it affect the graph's steepness?
2. How do you calculate the y-intercept from an equation in slope-intercept form?
3. If the slope were steeper, how would that change the graph of the line?
4. What does the domain represent in the context of graphing a function?
5. How can you check if a point lies on a given line?

Tip: Always start by identifying the slope and y-intercept from the equation when graphing linear equations.