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The image shows a math problem asking to graph the equation \( y = \frac{1}{4}x + 5 \), with a domain of \( D: [-8, -4, 0, 4] \).

Let's break this down:

1. **Equation of the line**: \( y = \frac{1}{4}x + 5 \) is a linear equation with a slope of \( \frac{1}{4} \) and a y-intercept of 5. This means the line rises by 1 unit for every 4 units it moves to the right.

2. **Given domain**: \( D: [-8, -4, 0, 4] \) means you are asked to graph the line for the x-values: \( -8, -4, 0, 4 \).

3. **To find the points on the graph**:
    - When \( x = -8 \): 
      \[
      y = \frac{1}{4}(-8) + 5 = -2 + 5 = 3
      \]
    - When \( x = -4 \): 
      \[
      y = \frac{1}{4}(-4) + 5 = -1 + 5 = 4
      \]
    - When \( x = 0 \): 
      \[
      y = \frac{1}{4}(0) + 5 = 5
      \]
    - When \( x = 4 \): 
      \[
      y = \frac{1}{4}(4) + 5 = 1 + 5 = 6
      \]

4. **Plotting points**:
    - \( (-8, 3) \)
    - \( (-4, 4) \)
    - \( (0, 5) \)
    - \( (4, 6) \)

5. **Graph**: Now, these points would form a line when plotted on the grid.

Would you like me to explain the graphing process further or have any questions?

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Here are 5 related questions to deepen your understanding:
1. What is the slope of a line and how does it affect the graph's steepness?
2. How do you calculate the y-intercept from an equation in slope-intercept form?
3. If the slope were steeper, how would that change the graph of the line?
4. What does the domain represent in the context of graphing a function?
5. How can you check if a point lies on a given line?

**Tip**: Always start by identifying the slope and y-intercept from the equation when graphing linear equations.

Graph the equation y = (1/4)x + 5 with the domain D: [-8, -4, 0, 4].

Learn how to graph the linear equation y = (1/4)x + 5, focusing on key algebraic concepts such as slope, y-intercept, and domain. This example is ideal for students in Grades 8-10 learning how to plot points and draw linear graphs.

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