The problem asks to write an equation in slope-intercept form for a line with slope $m = 2$ and $y$-intercept $b = 4$, and then graph the line.

Slope-intercept form:

The general form of a linear equation in slope-intercept form is:

$y = mx + b$

Where:

• $m$ is the slope,
• $b$ is the $y$-intercept.

In this case:

• $m = 2$ (given slope),
• $b = 4$ (given $y$-intercept).

Equation of the line:

Using the values of $m$ and $b$:

$y = 2x + 4$

This is the equation in slope-intercept form.

Graphing:

1. The line crosses the $y$-axis at $(0, 4)$.
2. From this point, apply the slope $m = 2$. This means for every 1 unit you move to the right (along the $x$-axis), the line moves 2 units up (along the $y$-axis).

If you plot these points, you will be able to graph the line.

Would you like more details or assistance with the graphing?

Related Questions:

1. What is the slope-intercept form for a line with slope $-3$ and $y$-intercept $5$?
2. How do you convert a standard form equation into slope-intercept form?
3. What happens to the line if the slope becomes zero?
4. How do parallel and perpendicular lines relate to the slope of a line?
5. Can you find the $x$-intercept of the line $y = 2x + 4$?

Tip: The slope tells you how steep a line is, and the $y$-intercept tells you where the line crosses the $y$-axis.