Math Problem Statement

Part 2 of 2

Question content area top left

Part 1

Use transformations of

f left parenthesis x right parenthesis equals x squaredf(x)=x2

to graph the following function.

g left parenthesis x right parenthesis equals negative 2 left parenthesis x plus 3 right parenthesis squared minus 2g(x)=−2(x+3)2−2

Question content area bottom left

Part 1

Select all the transformations that are needed to graph the given function using

f left parenthesis x right parenthesis equals x squaredf(x)=x2.

A.

Shift the graph

33

unitsunits

to the

leftleft.

Your answer is correct.

B.

Reflect the graph about the​ x-axis.

Your answer is correct.

C.

Shift the graph

22

unitsunits

downdown.

Your answer is correct.

D.

Shift the graph

22

unitsunits

upup.

E.

Stretch the graph vertically by a factor of

Your answer is correct.

F.

Shrink the graph vertically by a factor of

G.

Reflect the graph about the​ y-axis.

H.

Stretch the graph horizontally by a factor of

I.

Shift the graph

33

unitsunits

to the

rightright.

J.

Shrink the graph horizontally by a factor of

Part 2

Use the graphing tool to graph the function.

Click to enlarge graph

...

Question content area right

Part 1

-10-8-6-4-2246810-10-8-6-4-2246810xy

interactive graph

Select all the transformations that are needed to graph the given function using f left parenthesis x right parenthesis equals x squared.

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Solution

In the second part of the problem, you're asked to use a graphing tool to plot the function g(x)=2(x+3)22g(x) = -2(x + 3)^2 - 2 based on the transformations identified in the first part. Here’s how you would graph the function step-by-step:

Step-by-Step Guide to Graphing g(x)g(x):

  1. Start with the Base Graph:

    • Begin with the graph of f(x)=x2f(x) = x^2, which is a parabola opening upwards with its vertex at the origin (0,0)(0, 0).
  2. Apply Transformations:

    • Horizontal Shift (3 units to the left):

      • Move the entire graph 3 units to the left. The new vertex of the parabola is now at (3,0)(-3, 0).
    • Reflection about the x-axis:

      • Reflect the graph over the x-axis. The parabola, which initially opened upwards, will now open downwards. The vertex remains at (3,0)(-3, 0).
    • Vertical Stretch by a factor of 2:

      • Stretch the parabola vertically by a factor of 2, making it narrower. This affects the "width" of the parabola, making it steeper.
    • Vertical Shift (2 units down):

      • Finally, shift the entire graph 2 units down. The vertex moves to (3,2)(-3, -2).

Final Graph:

  • The vertex of the transformed parabola is at (3,2)(-3, -2).
  • The parabola opens downwards.
  • It is narrower than the standard parabola due to the vertical stretch.

Using the Graphing Tool:

  • Plot the vertex at (3,2)(-3, -2).
  • Draw the parabola opening downwards with a narrower shape compared to the base graph of f(x)=x2f(x) = x^2.
  • Ensure the axis of symmetry is the line x=3x = -3.

This should correctly represent the function g(x)=2(x+3)22g(x) = -2(x + 3)^2 - 2 based on the transformations.


Do you have any questions on how to use the graphing tool or need further clarification on the transformations?

Related Questions:

  1. How would the graph change if the coefficient in front of (x+3)2(x + 3)^2 was 1-1 instead of 2-2?
  2. What would be the vertex of the graph if the function was g(x)=2(x3)2+4g(x) = -2(x - 3)^2 + 4?
  3. How do you determine the axis of symmetry for a quadratic function?
  4. How does a vertical stretch or shrink affect the shape of a parabola?
  5. What are the effects of combining horizontal and vertical shifts on the vertex of the graph?

Tip: When using graphing tools, always mark the vertex and the direction the parabola opens first. This will help you sketch the graph more accurately.

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Math Problem Analysis

Mathematical Concepts

Quadratic Functions
Transformations of Functions

Formulas

-

Theorems

-

Suitable Grade Level

High School