Math Problem Statement

A battery with [20%] of its full capacity is connected to a charger. Every minute that passes, an additional [5%] of its capacity is charged. Graph the relationship between the battery's capacity (in [%] charged) and time (in minutes).

Solution

To graph the relationship between the battery's capacity and time, we first need to define the variables:

  • Let tt represent time in minutes.
  • Let C(t)C(t) represent the battery's capacity at time tt (in percentage, %).

Given:

  • Initially, the battery has 20% of its full capacity, so C(0)=20%C(0) = 20\%.
  • Every minute, the battery gains an additional 5% of its capacity. Thus, the rate of change of the battery's capacity is 5% per minute.

We can model the battery's capacity as a linear function because the increase is constant every minute. The function can be written as:

C(t)=20+5tC(t) = 20 + 5t

Where:

  • C(t)C(t) is the battery's capacity at time tt,
  • 2020 is the initial capacity (20%),
  • 5t5t represents the 5% increase per minute.

Now, we need to consider the domain:

  • The battery can never exceed 100% capacity, so we need to find when C(t)C(t) reaches 100%.

Setting C(t)=100C(t) = 100:

100=20+5t100 = 20 + 5t 5t=805t = 80 t=16t = 16

So, after 16 minutes, the battery will be fully charged (100%).

Graph:

  • The x-axis will represent time tt in minutes.
  • The y-axis will represent the battery capacity C(t)C(t) in percent.
  • The line will start at (0,20)(0, 20) and increase linearly by 5% every minute until it reaches (16,100)(16, 100).

The graph will be a straight line from (0,20)(0, 20) to (16,100)(16, 100), with a slope of 5.

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Math Problem Analysis

Mathematical Concepts

Linear Functions
Rate of Change
Graphing Linear Equations

Formulas

C(t) = 20 + 5t

Theorems

Linear Equation Theorem

Suitable Grade Level

Grades 7-9