From the graph, the two lines intersect at the point $(6, 3)$. This means:

• Oliver made 6 three-point shots ($x = 6$).
• Oliver made 3 two-point shots ($y = 3$).

These values satisfy both the conditions of the problem: the total points (6 three-pointers and 3 two-pointers give $6 \times 3 + 3 \times 2 = 24$ points) and the relationship (3 more three-point shots than two-point shots).

Would you like further details or have any questions?

5 Related Questions:

1. How do we verify the solution algebraically instead of graphically?
2. What if Oliver made 5 more three-point shots than two-point shots? How would the system of equations change?
3. How can we solve this system using substitution or elimination methods instead of graphing?
4. What happens if Oliver scored a total of 30 points under the same conditions?
5. How would you model this problem if Oliver also made some free throws worth 1 point?

Tip:

When solving systems of equations graphically, always look for the point of intersection—this represents the solution where both conditions are satisfied simultaneously.