identify corner points: Solve the system​ graphically, and indicate whether the solution region is bounded or unbounded. Find the coordinates of each corner point.

3 x plus y3x+y

greater than or equals≥

1515

x plus 2 yx+2y

greater than or equals≥

10

x

greater than or equals≥

0

y

greater than or equals≥

0

To solve the given system of inequalities graphically and identify the corner points, we can follow these steps:

1. **Rewrite the inequalities**:
   - \(3x + y \geq 15\)
   - \(x + 2y \geq 10\)
   - \(x \geq 0\)
   - \(y \geq 0\)

2. **Convert inequalities to equations**:
   - From \(3x + y = 15\)
   - From \(x + 2y = 10\)

3. **Find the intersection points**:
   - Solve \(3x + y = 15\) and \(x + 2y = 10\) simultaneously.

4. **Graph the lines**:
   - Plot the equations \(3x + y = 15\) and \(x + 2y = 10\) in the first quadrant (since \(x \geq 0\) and \(y \geq 0\)).

5. **Identify corner points**:
   - The points where the lines intersect, as well as where they intersect the axes, will provide the corner points.

### Step-by-Step Calculations:

1. **Finding intersection points**:
   - From \(3x + y = 15\):
     \[
     y = 15 - 3x
     \]
   - Substitute into \(x + 2y = 10\):
     \[
     x + 2(15 - 3x) = 10 \implies x + 30 - 6x = 10 \implies -5x = -20 \implies x = 4
     \]
     Then substituting \(x = 4\) back to find \(y\):
     \[
     y = 15 - 3(4) = 15 - 12 = 3
     \]
   - So one intersection point is \((4, 3)\).

2. **Finding intercepts**:
   - For \(3x + y = 15\):
     - \(x\)-intercept: \(y = 0 \Rightarrow 3x = 15 \Rightarrow x = 5\) \(\Rightarrow (5, 0)\)
     - \(y\)-intercept: \(x = 0 \Rightarrow y = 15\) \(\Rightarrow (0, 15)\)

   - For \(x + 2y = 10\):
     - \(x\)-intercept: \(y = 0 \Rightarrow x = 10\) \(\Rightarrow (10, 0)\)
     - \(y\)-intercept: \(x = 0 \Rightarrow 2y = 10 \Rightarrow y = 5\) \(\Rightarrow (0, 5)\)

3. **Identifying the feasible region**:
   - We plot the points: \((4, 3)\), \((5, 0)\), \((0, 15)\), \((10, 0)\), and \((0, 5)\) on a graph.
   - The region satisfying all inequalities will be bounded by these lines and the axes.

### Summary of Corner Points:
The corner points of the feasible region are:
1. \((5, 0)\)
2. \((0, 5)\)
3. \((4, 3)\)
4. \((0, 15)\)
5. \((10, 0)\) (but does not satisfy the \(3x + y \geq 15\) constraint)

### Conclusion:
- The feasible region is **bounded**.
- The valid corner points are:
  - \((5, 0)\)
  - \((0, 5)\)
  - \((4, 3)\)

If you have any further questions or need more details, let me know! Here are some follow-up questions you might consider:

1. How do I graph these inequalities on a coordinate plane?
2. What does it mean for a region to be bounded or unbounded?
3. Can you provide examples of other inequalities and their graphical solutions?
4. How do the corner points relate to optimization problems?
5. What other methods can be used to solve systems of inequalities besides graphical methods?

**Tip**: Always check that the corner points satisfy all original inequalities to confirm they are part of the feasible region.

Identify corner points: Solve the system graphically, and indicate whether the solution region is bounded or unbounded. Find the coordinates of each corner point.

Explore how to solve a system of inequalities graphically, identify corner points, and determine if the solution region is bounded or unbounded. The problem involves the inequalities 3x + y ≥ 15 and x + 2y ≥ 10, leading to valid corner points (5, 0), (0, 5), and (4, 3).

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