Math Problem Statement

Use transformations of f(x) = x^2 to graph the following function. h(x) = (x + 5)^2 + 4.

Solution

The problem is asking to graph the function h(x)=(x+5)2+4h(x) = (x + 5)^2 + 4 using transformations of f(x)=x2f(x) = x^2.

Analyzing the function h(x)=(x+5)2+4h(x) = (x + 5)^2 + 4:

  1. The base function is f(x)=x2f(x) = x^2, which is a standard parabola with its vertex at the origin (0,0).
  2. The transformation (x+5)2(x + 5)^2 implies a horizontal shift to the left by 5 units.
  3. The transformation +4+4 at the end represents a vertical shift up by 4 units.

Therefore, the function h(x)=(x+5)2+4h(x) = (x + 5)^2 + 4 is the graph of f(x)=x2f(x) = x^2, shifted 5 units to the left and 4 units upward. This matches option A: "The graph of f(x)=x2f(x) = x^2 should be horizontally shifted to the left by 5 units and vertically shifted up by 4 units."

Would you like more details on graph transformations, or do you have any questions?

Related Questions:

  1. What is a horizontal shift in a graph?
  2. How do vertical shifts affect the graph of a function?
  3. Can transformations apply to other types of functions, like cubic or absolute value functions?
  4. What is the vertex of a parabola, and how do shifts affect it?
  5. How would you describe the transformation of f(x)=x2f(x) = x^2 into h(x)=(x3)22h(x) = (x - 3)^2 - 2?

Tip: Horizontal shifts are always in the opposite direction of the sign inside the function. For example, (x+5)(x + 5) means a shift to the left, not the right!

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Math Problem Analysis

Mathematical Concepts

Graph Transformations
Quadratic Functions

Formulas

f(x) = a(x-h)^2 + k

Theorems

Graph Transformation Theorem for Quadratic Functions

Suitable Grade Level

Grades 9-10