Math Problem Statement

Suppose left parenthesis 8 comma negative 4 right parenthesis(8,−4) is a point on the graph of yequals=​f(x). ​(a) What point is on the graph of y equals f left parenthesis x plus 2 right parenthesis minus 1y=f(x+2)−1​? ​(b) What point is on the graph of y equals negative 2 f left parenthesis x minus 7 right parenthesis plus 9y=−2f(x−7)+9​? ​(c) What point is on the graph of y equals f left parenthesis 2 x plus 2 right parenthesisy=f(2x+2)​?

Solution

Let's break down the transformations one by one based on the given point (8,4)(8, -4) on the graph of y=f(x)y = f(x).

Part (a): y=f(x+2)1y = f(x+2) - 1

  • Horizontal shift: The function is shifted to the left by 2 units. This means that the new xx-value is 82=68 - 2 = 6.
  • Vertical shift: The graph is shifted downward by 1 unit. This means the new yy-value is 41=5-4 - 1 = -5.

Thus, the new point is (6,5)(6, -5).

Part (b): y=2f(x7)+9y = -2f(x-7) + 9

  • Horizontal shift: The function is shifted to the right by 7 units. This means that the new xx-value is 8+7=158 + 7 = 15.
  • Vertical scaling and shift: First, the function is vertically scaled by a factor of 2-2, so the new yy-value becomes 2(4)=8-2(-4) = 8. Then, it is shifted upward by 9 units, so the final yy-value is 8+9=178 + 9 = 17.

Thus, the new point is (15,17)(15, 17).

Part (c): y=f(2x+2)y = f(2x+2)

  • Horizontal scaling and shift: The argument of ff is 2x+22x+2, which can be factored as 2(x+1)2(x+1). This represents a horizontal compression by a factor of 12\frac{1}{2} and a shift to the left by 1 unit. To find the new xx-value, set 2x+2=82x + 2 = 8 (the original xx-value) and solve for xx:

2x+2=82x=6x=32x + 2 = 8 \quad \Rightarrow \quad 2x = 6 \quad \Rightarrow \quad x = 3

Thus, the new point is (3,4)(3, -4), since the yy-value doesn't change in this transformation.

Summary:

  • (a) The new point is (6,5)(6, -5).
  • (b) The new point is (15,17)(15, 17).
  • (c) The new point is (3,4)(3, -4).

Would you like more details on any part of these transformations?


Here are five related questions:

  1. How do horizontal shifts affect the graph of a function?
  2. What is the impact of vertical scaling by a negative number on a graph?
  3. How do you interpret y=f(2x)y = f(2x) in terms of graph transformations?
  4. What happens when a function is shifted both vertically and horizontally?
  5. How do transformations involving multiple operations (like scaling and shifting) work?

Tip: When dealing with transformations, always start by analyzing horizontal changes before applying vertical ones!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Function Transformations
Graph Shifting
Scaling
Horizontal and Vertical Shifts

Formulas

Horizontal shift: y = f(x ± h)
Vertical shift: y = f(x) ± k
Vertical scaling: y = a * f(x)
Horizontal scaling: y = f(b * x)

Theorems

Transformation Theorems for Functions: Describes how graphs of functions are altered by horizontal and vertical shifts, as well as scaling.

Suitable Grade Level

Grades 9-12