Math Problem Statement

Graph h(x) = 2f(x) - 1, where the original graph of f(x) is provided as a piecewise linear function.

Solution

You have provided the graph of the function f(x)f(x), and you're looking to graph h(x)=2f(x)1h(x) = 2f(x) - 1.

Transformation Breakdown:

  1. Vertical Stretch by a factor of 2: The factor of 2 in 2f(x)2f(x) stretches the graph of f(x)f(x) vertically by multiplying all yy-values by 2.
  2. Vertical Shift down by 1: The term 1-1 shifts the graph down by 1 unit.

Applying Transformations:

  • Start with f(x)f(x). The given graph seems to be piecewise linear, with key points:
    • (3,0)(-3, 0)
    • (2,2)(-2, 2)
    • (0,2)(0, 2)
    • (2,2)(2, 2)
    • (3,0)(3, 0)

For each key point:

  • Stretch by 2: Multiply the yy-coordinate by 2.
  • Shift down by 1: Subtract 1 from the yy-coordinate.

Let's calculate the new points for h(x)=2f(x)1h(x) = 2f(x) - 1:

xxf(x)f(x)2f(x)2f(x)2f(x)12f(x) - 1
-300-1
-2243
0243
2243
300-1

So, the points on the graph of h(x)h(x) are:

  • (3,1)(-3, -1)
  • (2,3)(-2, 3)
  • (0,3)(0, 3)
  • (2,3)(2, 3)
  • (3,1)(3, -1)

These points outline the new shape of h(x)h(x).

Would you like more details or an explanation of how to plot this? Here are a few related questions:

  1. How do you identify key points on a piecewise graph?
  2. How do different transformations (vertical stretch, shrink, translation) affect a graph?
  3. Can horizontal shifts and stretches be combined with vertical ones?
  4. How would the transformation change if the function was h(x)=2f(x)+3h(x) = -2f(x) + 3?
  5. How can you graph transformations efficiently without recalculating each point?

Tip: When transforming graphs, always handle stretches first before applying translations.

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Math Problem Analysis

Mathematical Concepts

Function Transformation
Piecewise Functions
Graphing

Formulas

h(x) = 2f(x) - 1
Vertical Stretch and Shift

Theorems

Transformation Theorem: Vertical Stretch and Translation

Suitable Grade Level

Grades 9-12