Math Problem Statement
Solution
The equation given in the image is:
This is a quadratic equation of the form , where , , and .
Steps to graph the function:
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Find the vertex: The vertex of a parabola can be found using the formula for the x-coordinate of the vertex: Substituting and : Now, substitute back into the equation to find the y-coordinate of the vertex: The vertex is at .
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Determine the direction: Since is positive, the parabola opens upwards.
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Find the y-intercept: The y-intercept occurs when . Substituting into the equation: The y-intercept is .
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Find the x-intercepts (if any): The x-intercepts occur when . Solve the equation using the quadratic formula: Substituting , , and : So, the two solutions are: The x-intercepts are approximately and .
Plotting the graph:
- The vertex is at .
- The parabola opens upwards.
- The y-intercept is .
- The x-intercepts are approximately and .
Would you like a detailed graph or further explanation?
Related Questions:
- How do you find the axis of symmetry of a quadratic function?
- Can a parabola ever open downward, and how does that affect its vertex?
- How does the value of in the quadratic equation affect the shape of the graph?
- What are the implications of complex roots in a quadratic equation?
- How can the quadratic formula be derived from completing the square?
Tip: Always check the sign of in the quadratic equation to determine if the parabola opens upwards or downwards.
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Math Problem Analysis
Mathematical Concepts
Quadratic Equations
Parabolas
Vertex
Intercepts
Formulas
Vertex formula: x = -b / 2a
Quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a
Theorems
Quadratic formula
Symmetry of a parabola
Suitable Grade Level
Grades 9-11