Math Problem Statement

Draw the graph of radius 1/sin theta

Solution

Here is the graph of the polar function r=1sinθr = \frac{1}{\sin \theta}.

  • As expected, there are vertical asymptotes at θ=0,π,2π\theta = 0, \pi, 2\pi, where sinθ=0\sin \theta = 0, and the function becomes undefined.
  • The graph is symmetric about the y-axis and exhibits large values as it approaches the asymptotes.

Would you like more details about this graph or its behavior?

Here are some related questions to explore further:

  1. How does the graph of r=1cosθr = \frac{1}{\cos \theta} compare to this one?
  2. What happens if we modify the equation to r=1sin2θr = \frac{1}{\sin^2 \theta}?
  3. Can you explain the behavior of polar graphs for other trigonometric functions?
  4. How does symmetry in polar graphs work for different functions?
  5. What does the graph of r=1sin(θ+π4)r = \frac{1}{\sin(\theta + \frac{\pi}{4})} look like?

Tip: When analyzing polar graphs, always check for points where the function might become undefined or infinite.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Polar Coordinates
Graphing Functions

Formulas

r = 1/sin(θ)

Theorems

Polar Function Behavior
Vertical Asymptotes

Suitable Grade Level

Grades 10-12