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The image asks to move the red point so that it lies on the line given by the equation:

\[
4x - y + 3 = 0
\]

We can solve for \(y\) in terms of \(x\) to express this as a slope-intercept form equation. 

Starting from:

\[
4x - y + 3 = 0
\]

Solve for \(y\):

\[
y = 4x + 3
\]

Now, we need to identify a point on this line where the red point should be placed. Let me calculate some points on this line by selecting a few values of \(x\).

I'll calculate those now.Here are some points on the line \(4x - y + 3 = 0\):

- When \(x = -2\), \(y = -5\)
- When \(x = -1\), \(y = -1\)
- When \(x = 0\), \(y = 3\)
- When \(x = 1\), \(y = 7\)
- When \(x = 2\), \(y = 11\)

The red point should be moved to one of these points to ensure it lies on the line. For instance, moving the red point to \((0, 3)\) will satisfy the equation.

Would you like to know more details or have questions?

Here are some related questions:
1. How can you find the slope of the line from the equation?
2. How do you determine the y-intercept from a linear equation?
3. What does the point \((0, 3)\) represent on the graph?
4. How do you check if any point lies on a given line?
5. Can you find the equation of a line passing through two points?

**Tip:** When graphing, the slope tells you how steep the line is, and the y-intercept shows where it crosses the y-axis.

Move the red point so that it lies on the line 4x - y + 3 = 0.

Learn how to move a point to lie on the line 4x - y + 3 = 0. This problem focuses on linear equations and graphing techniques, suitable for students in Grades 8-10. Follow a step-by-step solution to determine the point's position on the line.

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