Titik puncak (vertex):
(
5
,
3
)
(5,3)
Akar-akar:
X
1
=
4
X
1
​
=4 dan
X
2
=
6
X
2
​
=6
Parabola terbuka ke bawah karena
a
=
−
3
a=−3 gambarkan parabolanya

Here is the graph of the parabola with the given information:
- Vertex at \((5, 3)\)
- Roots (or x-intercepts) at \(x_1 = 4\) and \(x_2 = 6\)
- The parabola opens downward because \(a = -3\).

Would you like any further details or have any questions?

Here are 5 related questions to explore further:
1. How do we find the equation of a parabola given its vertex and roots?
2. Why does the value of \(a = -3\) affect the direction in which the parabola opens?
3. How can we use the vertex form to derive the standard form of a quadratic equation?
4. What happens to the shape of the parabola if the value of \(a\) is changed?
5. How can we determine the axis of symmetry of a parabola from its equation?

**Tip:** The axis of symmetry for any parabola in vertex form \(y = a(x - h)^2 + k\) is always the vertical line \(x = h\).

Titik puncak (vertex): (5,3), Akar-akar: X1=4 dan X2=6. Parabola terbuka ke bawah karena a=-3 gambarkan parabolanya.

Explore how to graph a parabola with a vertex at (5,3), roots at x = 4 and x = 6, and the parabola opening downward due to a = -3. This problem demonstrates key concepts such as the vertex form of a parabola and symmetry. Suitable for students in Grades 9-11.

Math Problem Statement

Titik puncak (vertex): ( 5 , 3 ) (5,3) Akar-akar: X 1

4 X 1 =4 dan X 2

6 X 2 =6 Parabola terbuka ke bawah karena a

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