Math Problem Statement

The graph of [y=\log_2x] is shown below.

[\small{2}] [\small{4}] [\small{6}] [\small{8}] [\small{\llap{-}4}] [\small{\llap{-}6}] [\small{\llap{-}8}] [\small{2}] [\small{4}] [\small{6}] [\small{8}] [\small{\llap{-}4}] [\small{\llap{-}6}] [\small{\llap{-}8}] [y] [x] Which of the following is the graph of [y=\log_2(-x)+3]? Choose 1 answer: Choose 1 answer: (Choice A)   [\small{2}] [\small{4}] [\small{6}] [\small{8}] [\small{\llap{-}4}] [\small{\llap{-}6}] [\small{\llap{-}8}] [\small{2}] [\small{4}] [\small{6}] [\small{8}] [\small{\llap{-}4}] [\small{\llap{-}6}] [\small{\llap{-}8}] [y] [x] [\normalsize{\text{A}}]

A

[\small{2}] [\small{4}] [\small{6}] [\small{8}] [\small{\llap{-}4}] [\small{\llap{-}6}] [\small{\llap{-}8}] [\small{2}] [\small{4}] [\small{6}] [\small{8}] [\small{\llap{-}4}] [\small{\llap{-}6}] [\small{\llap{-}8}] [y] [x] [\normalsize{\text{A}}] (Choice B)   [\small{2}] [\small{4}] [\small{6}] [\small{8}] [\small{\llap{-}4}] [\small{\llap{-}6}] [\small{\llap{-}8}] [\small{2}] [\small{4}] [\small{6}] [\small{8}] [\small{\llap{-}4}] [\small{\llap{-}6}] [\small{\llap{-}8}] [y] [x] [\normalsize{\text{B}}]

B

[\small{2}] [\small{4}] [\small{6}] [\small{8}] [\small{\llap{-}4}] [\small{\llap{-}6}] [\small{\llap{-}8}] [\small{2}] [\small{4}] [\small{6}] [\small{8}] [\small{\llap{-}4}] [\small{\llap{-}6}] [\small{\llap{-}8}] [y] [x] [\normalsize{\text{B}}] (Choice C)   [\small{2}] [\small{4}] [\small{6}] [\small{8}] [\small{\llap{-}4}] [\small{\llap{-}6}] [\small{\llap{-}8}] [\small{2}] [\small{4}] [\small{6}] [\small{8}] [\small{\llap{-}4}] [\small{\llap{-}6}] [\small{\llap{-}8}] [y] [x] [\normalsize{\text{C}}]

C

[\small{2}] [\small{4}] [\small{6}] [\small{8}] [\small{\llap{-}4}] [\small{\llap{-}6}] [\small{\llap{-}8}] [\small{2}] [\small{4}] [\small{6}] [\small{8}] [\small{\llap{-}4}] [\small{\llap{-}6}] [\small{\llap{-}8}] [y] [x] [\normalsize{\text{C}}] (Choice D)   [\small{2}] [\small{4}] [\small{6}] [\small{8}] [\small{\llap{-}4}] [\small{\llap{-}6}] [\small{\llap{-}8}] [\small{2}] [\small{4}] [\small{6}] [\small{8}] [\small{\llap{-}4}] [\small{\llap{-}6}] [\small{\llap{-}8}] [y] [x] [\normalsize{\text{D}}]

D

[\small{2}] [\small{4}] [\small{6}] [\small{8}] [\small{\llap{-}4}] [\small{\llap{-}6}] [\small{\llap{-}8}] [\small{2}] [\small{4}] [\small{6}] [\small{8}] [\small{\llap{-}4}] [\small{\llap{-}6}] [\small{\llap{-}8}] [y] [x] [\normalsize{\text{D}}] Related content

Solution

The equation given is y=log2(x)+3y = \log_2(-x) + 3. To understand the transformation, let's break it down:

  1. y=log2(x)y = \log_2(x): This is the standard logarithmic function with base 2. The graph of this function passes through the point (1,0), has a vertical asymptote at x=0x = 0, and increases as xx increases.

  2. Transformation for y=log2(x)y = \log_2(-x):

    • The negative sign in front of xx reflects the graph across the y-axis.
    • So, the graph of y=log2(x)y = \log_2(-x) will be a mirror image of the graph of y=log2(x)y = \log_2(x) reflected over the y-axis.
  3. Transformation for y=log2(x)+3y = \log_2(-x) + 3:

    • The +3+3 shifts the entire graph upwards by 3 units.

To summarize:

  • The graph of y=log2(x)+3y = \log_2(-x) + 3 will be a reflection of y=log2(x)y = \log_2(x) across the y-axis and shifted upward by 3 units.

Now, we can use these transformations to find the correct graph.

Conclusion:

  • The graph of y=log2(x)+3y = \log_2(-x) + 3 will show:
    • A reflection of the original graph across the y-axis.
    • A vertical shift of 3 units upwards.

Given this, the graph that reflects these transformations will be Choice B.

Would you like a further explanation or clarification?

Here are a few related questions:

  1. How does a reflection across the x-axis affect the graph of a logarithmic function?
  2. What happens to the domain of the logarithmic function y=log2(x)+3y = \log_2(-x) + 3?
  3. How do you shift the graph of y=log2(x)y = \log_2(x) to the left or right?
  4. What is the effect of adding a constant outside the logarithmic function?
  5. How would you graph y=log2(x)y = \log_2(x) on a graphing calculator?

Tip: Always remember that the domain of y=logb(x)y = \log_b(x) is x>0x > 0, but for transformations, the domain can be adjusted accordingly.

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Math Problem Analysis

Mathematical Concepts

Logarithmic Functions
Graph Transformations
Reflections
Vertical Shifts

Formulas

y = log_2(x)
y = log_2(-x)
y = log_2(-x) + 3

Theorems

Reflection of graphs
Vertical shift of graphs

Suitable Grade Level

Grades 9-12