The task requires graphing a line with the following properties:

• Slope = 2
• Y-intercept = 3

The general equation for a line in slope-intercept form is: $y = mx + b$ where $m$ is the slope and $b$ is the y-intercept.

Given:

• $m = 2$ (slope)
• $b = 3$ (y-intercept)

The equation of the line would be: $y = 2x + 3$

In the graph you uploaded, it seems there is a misunderstanding in the line's plot. The correct graph should:

1. Pass through the y-intercept at $(0, 3)$.
2. Have a slope of 2, which means for every unit increase in $x$, $y$ should increase by 2 units. So, moving from $(0, 3)$, the next point could be $(1, 5)$ (since $y = 2(1) + 3 = 5$).

Let me know if you'd like a corrected graph drawn out, or if you have questions about the process!

Here are 5 related questions for further learning:

1. How can you find the slope if given two points on a line?
2. What changes in the equation of a line when the slope is negative?
3. How do you determine the x-intercept from a line equation?
4. How does the graph of a line change if you increase the y-intercept?
5. What is the difference between slope-intercept form and point-slope form?

Tip: When graphing, always check if the line passes through the correct y-intercept and follows the slope!