Let's analyze the task based on the images:

1. First image: You plotted the graph, and the yellow vertical line at $x = 0$ seems to represent the y-axis. The blue dot at $(0, 4)$ corresponds to the y-intercept.

2. Second image: The problem involves graphing the equation $x + 5y = 20$ and identifying the y-intercept.

   To determine the y-intercept, we can set $x = 0$ in the equation $x + 5y = 20$: $0 + 5y = 20 \implies y = \frac{20}{5} = 4$ So, the y-intercept is $(0, 4)$, which matches the point marked in your graph.

Therefore, your drawing is correct: the y-intercept is indeed $(0, 4)$.

Do you have any questions or would you like further clarification?

Here are 5 related questions to further expand your understanding:

1. What would be the slope of the line represented by $x + 5y = 20$?
2. How do you find the x-intercept for the same equation?
3. Can you rewrite the equation $x + 5y = 20$ in slope-intercept form?
4. What would happen to the graph if the equation were $x + 5y = 15$?
5. How does changing the coefficient of $y$ in the equation affect the slope of the line?

Tip: Always double-check by substituting points from the graph into the equation to ensure accuracy.