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The given equation is \( y = -\frac{1}{2}x + 3 \). This represents a linear equation in slope-intercept form \( y = mx + b \), where:

- \( m = -\frac{1}{2} \) is the slope.
- \( b = 3 \) is the y-intercept, which means the line crosses the y-axis at \( y = 3 \).

### Steps to graph the line:
1. **Plot the y-intercept (0, 3):**
   Start by plotting the point where the line crosses the y-axis. This is the point \( (0, 3) \).

2. **Use the slope to find another point:**
   The slope \( -\frac{1}{2} \) means that for every 2 units you move to the right (positive direction of x-axis), you move 1 unit down (since the slope is negative). Starting from \( (0, 3) \), move:
   - 2 units to the right to \( x = 2 \),
   - 1 unit down to \( y = 2 \).

   This gives you a second point: \( (2, 2) \).

3. **Draw the line:**
   Now, draw a straight line passing through the points \( (0, 3) \) and \( (2, 2) \). You can extend this line in both directions.

Would you like more details or have any questions? 

Here are five related questions for further practice:
1. What is the slope of the line \( y = \frac{2}{3}x - 1 \)?
2. How would you graph the equation \( y = -3x + 5 \)?
3. What does it mean if a line has a slope of zero?
4. How do you determine the x-intercept of a line?
5. How does changing the slope affect the steepness of a line?

**Tip:** The slope \( m \) tells you how the line rises or falls as you move along the x-axis.

Learn how to graph the line represented by the equation y = -1/2x + 3. This problem covers key concepts such as slope and y-intercept, with step-by-step instructions on plotting points and drawing the line. Suitable for students in Grades 7-9.

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