Math Problem Statement

graph and identify the parts of this circle (x-5/2)²+(y-4)²=2

Solution

The given equation is:

(x52)2+(y4)2=2\left( x - \frac{5}{2} \right)^2 + (y - 4)^2 = 2

This is the equation of a circle in standard form:

(xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2

Where:

  • (h,k)(h, k) is the center of the circle.
  • rr is the radius of the circle.

Identifying the parts:

  1. Center: From the equation, (h,k)(h, k) represents the center. Here:

    • h=52=2.5h = \frac{5}{2} = 2.5
    • k=4k = 4

    Therefore, the center of the circle is (2.5,4)(2.5, 4).

  2. Radius: The right-hand side of the equation is r2r^2. Here:

    • r2=2r^2 = 2
    • Therefore, r=2r = \sqrt{2} (approximately 1.4141.414).
  3. Graph of the circle:

    • The center is located at (2.5,4)(2.5, 4).
    • The radius is 2\sqrt{2}, so the distance from the center to any point on the circle is approximately 1.4141.414 units.

Would you like me to graph this circle for you? Also, feel free to ask any further questions.


Here are 5 related questions for you to explore:

  1. How do you find the equation of a circle given three points on its circumference?
  2. What is the significance of completing the square in deriving a circle equation?
  3. How do you determine the tangent line to a circle at a given point?
  4. How do you find the area of a sector of a circle given the radius and angle?
  5. How would you write the equation of a circle if its center is at the origin?

Tip: When solving equations involving circles, knowing how to complete the square can be essential for converting general forms into standard forms.

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Math Problem Analysis

Mathematical Concepts

Geometry
Circles
Equation of a Circle

Formulas

Standard form of a circle equation: (x - h)^2 + (y - k)^2 = r^2

Theorems

Properties of circles
Pythagorean theorem (used in deriving the distance formula)

Suitable Grade Level

Grades 9-10