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Let's complete the table for \( y = x^3 + x - 3 \) by calculating the values for \( x = 1 \) and \( x = 2 \).

1. **For \( x = 1 \):**
   \[
   y = 1^3 + 1 - 3 = 1 + 1 - 3 = -1
   \]

2. **For \( x = 2 \):**
   \[
   y = 2^3 + 2 - 3 = 8 + 2 - 3 = 7
   \]

So, the completed table of values is:

\[
\begin{array}{|c|c|c|c|c|c|}
\hline
x & -2 & -1 & 0 & 1 & 2 \\
\hline
y & -13 & -3 & -3 & -1 & 7 \\
\hline
\end{array}
\]

Next, you would plot these points \((-2, -13)\), \((-1, -3)\), \((0, -3)\), \((1, -1)\), and \((2, 7)\) on the graph and draw a smooth curve passing through them to complete the graph of the function \( y = x^3 + x - 3 \).

Would you like me to provide more details or help with anything else?

Here are five related questions for further practice:

1. What is the value of \( y \) for \( x = 3 \) in the function \( y = x^3 + x - 3 \)?
2. Can you find the x-intercepts (roots) of the equation \( y = x^3 + x - 3 \)?
3. What is the derivative of \( y = x^3 + x - 3 \) and what does it represent on the graph?
4. How does the graph of \( y = x^3 + x - 3 \) change if you add 2 to the function, making it \( y = x^3 + x - 1 \)?
5. What are the turning points of the graph of \( y = x^3 + x - 3 \)?

**Tip:** When plotting cubic functions, make sure to check for turning points and inflection points to get the correct shape of the curve.

Complete the table of values for y = x^3 + x - 3 and draw the graph of y = x^3 + x - 3 for values of x from -2 to 2.

Solve and graph the cubic function y = x^3 + x - 3 for x values ranging from -2 to 2. This problem covers key algebraic concepts, including evaluating cubic functions and plotting points on a graph. Suitable for students in Grades 8-10.

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