The question asks to "Gambarkan grafik", which translates to "Draw the graph" for each of the given inequalities or equations:

a. $y - 1 \leq x \leq y + 1$

This is an inequality describing a band of lines between two bounds:

1. $x = y - 1$ (a line with slope 1 and intercept -1)
2. $x = y + 1$ (a line with slope 1 and intercept 1)

The solution region is the area between these two lines.

b. $y = |1 - |x||$

This is a compound absolute value function. To break it down:

1. $y = 1 - |x|$ gives a V-shaped graph inverted (since it opens downward) with a maximum at $(0, 1)$.
2. It has an additional absolute value around the whole expression, which will reflect this V-shape upwards.

c. $y \leq |x|$

This describes the region below the graph of $y = |x|$, which is a V-shaped graph opening upwards.

d. $|y| < 2|x|$

This represents two regions:

1. $y < 2|x|$ and $y > -2|x|$, which corresponds to a region between two lines: $y = 2x$ and $y = -2x$.

Would you like me to sketch these graphs or provide further clarification?

Related Questions:

1. How do you solve absolute value inequalities in general?
2. How would the graph of $y = |x - 1|$ differ from $y = |x|$?
3. What is the significance of absolute values when graphing linear inequalities?
4. How does reflecting a graph across the x-axis or y-axis affect its shape?
5. What are some common techniques for solving inequalities graphically?

Tip: When graphing inequalities, always shade the region representing the solution set.