Let's work through the problem systematically. The transistor is made of Germanium, and the current gain $\beta = 100$. We'll go step by step to find the required parameters:

i. Determine the base current $I_B$.

We can apply Kirchhoff’s Voltage Law (KVL) in the base loop to find $I_B$. The base-emitter voltage for a Germanium transistor is typically around 0.3V.

Base loop:

$V_{BB} = I_B R_B + V_{BE}$

Where:

• $V_{BB} = 5V$
• $R_B = 10k\Omega$
• $V_{BE} = 0.3V$ (for Germanium)

Substitute the values into the equation:

$5 = I_B \cdot 10k + 0.3$

Solve for $I_B$:

$I_B = \frac{5 - 0.3}{10k} = \frac{4.7}{10k} = 0.47 \text{ mA}$

Thus, the base current $I_B = 0.47 \text{ mA}$.

ii. Calculate the voltage drop $V_{CE}$ across the collector-emitter junction.

For $V_{CE}$, we'll use Kirchhoff’s Voltage Law (KVL) in the collector-emitter loop.

$V_{CC} = I_C \cdot R_C + V_{CE}$

Now, we know:

• $V_{CC} = 10V$
• $R_C = 100\Omega$
• $I_C = \beta \cdot I_B$

Since $\beta = 100$ and $I_B = 0.47 \text{ mA}$:

$I_C = 100 \times 0.47 \text{ mA} = 47 \text{ mA}$

Now substitute the values into the KVL equation:

$10V = 47 \text{ mA} \times 100\Omega + V_{CE}$

$10V = 4.7V + V_{CE}$

So,

$V_{CE} = 10V - 4.7V = 5.3V$

Thus, the voltage drop $V_{CE} = 5.3V$.

iii. Determine the total emitter current $I_E$.

The total emitter current $I_E$ is related to the base and collector currents by:

$I_E = I_B + I_C$

Substitute the values of $I_B$ and $I_C$:

$I_E = 0.47 \text{ mA} + 47 \text{ mA} = 47.47 \text{ mA}$

Thus, the emitter current $I_E = 47.47 \text{ mA}$.

Summary of Results:

• $I_B = 0.47 \text{ mA}$
• $V_{CE} = 5.3 \text{ V}$
• $I_E = 47.47 \text{ mA}$

Would you like more details or have any questions?

Here are 5 related questions to extend this topic:

1. How would the results change if the transistor were made of Silicon instead of Germanium?
2. What is the effect of changing $R_C$ to 200 ohms on the current $I_C$?
3. How can you calculate the power dissipated by the transistor in this circuit?
4. What happens to $I_B$ if $V_{BB}$ is increased to 6V?
5. How would varying $\beta$ affect the overall behavior of the circuit?

Tip: Always check the type of transistor (Germanium or Silicon) when calculating the base-emitter voltage $V_{BE}$, as it significantly affects the current calculations.