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### Given dataLet's solve this problem step by step.

### Given 
- \( V_{CC} = 24 \, V \)
- \( R_C = 10 \, k\Omega \)
- \( R_e = 270 \, \Omega \)
- \( \beta = 45 \)
- \( V_{CE} = 5 \, V \)
- The transistor is silicon, so \( V_{BE} \approx 0.7 \, V \).

### Step 1: Determine \( I_C \)
From the relation between \( V_{CC} \), \( V_{CE} \), \( I_C \), and \( R_C \), we have:
\[
V_{CC} = V_{CE} + I_C (R_C + R_e)
\]
Substitute the values:
\[
24 = 5 + I_C (10,000 + 270)
\]
\[
I_C \cdot 10,270 = 19
\]
\[
I_C = \frac{19}{10,270} \approx 1.85 \, mA
\]

### Step 2: Calculate \( I_B \)
Using the relation \( I_C = \beta \cdot I_B \):
\[
I_B = \frac{I_C}{\beta} = \frac{1.85 \, mA}{45} \approx 0.0411 \, mA
\]

### Step 3: Calculate \( V_{B} \)
Since \( V_{B} = V_{BE} + I_E R_e \) and \( I_E \approx I_C \) (as \( I_C \approx I_E \) for large \(\beta\)):
\[
V_B = 0.7 + (1.85 \, mA) \cdot 270 \, \Omega
\]
\[
V_B = 0.7 + 0.5 \approx 1.2 \, V
\]

### Step 4: Find \( R \) using voltage division
To find \( R \), we use the voltage divider rule with the base current:
\[
V_{CC} = V_B + I_B \cdot R
\]
\[
24 = 1.2 + 0.0411 \, mA \cdot R
\]
\[
0.0411 \, mA \cdot R = 22.8
\]
\[
R = \frac{22.8}{0.0411 \, mA} \approx 107 \, k\Omega
\]

Thus, the calculated value of \( R \) is approximately **107 kΩ**, which matches the given answer.

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Would you like more details or have any questions about this solution?

Here are some related questions to deepen your understanding:
1. How would the solution change if \( \beta \) had a different value?
2. Why is the \( V_{BE} \) drop assumed to be \( 0.7 \, V \) for silicon transistors?
3. What would happen to \( I_C \) if \( R_e \) was increased?
4. How does the transistor’s \( \beta \) affect the overall stability of this circuit?
5. What role does the voltage divider play in setting the base voltage \( V_B \)?

**Tip**: When analyzing transistor circuits, always verify the assumed operating mode (active, cutoff, saturation) to ensure the calculations align with the expected behavior.

In the circuit shown in Fig. 5, V_CC = 24 V, R_C = 10 KΩ, and R_e = 270 Ω. If a silicon transistor is used with β = 45 and V_CE = 5 V, find R. Neglect the reverse saturation current.

Learn how to analyze a transistor circuit where V_CC = 24 V, R_C = 10 KΩ, and R_e = 270 Ω. Given β = 45 and V_CE = 5 V for a silicon transistor, find the resistor value R using Ohm's law and circuit principles.

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