Math Problem Statement
ABCD is a rectangle. A parallelogram is AECF is constructed within the rectangle such that point E is on AB and point F is on CD. If the area of the parallelogram is three-fifths the area of the rectangle and the length of CB is 25% less than the length of EB, then by what percentage is the perimeter of the rectangle ABCD greater than the perimeter of the parallelogram AECF?
Solution
Let's analyze and solve the problem step by step.
Step 1: Define Variables
Let:
- The length of (the longer side of the rectangle).
- The length of (the shorter side of the rectangle).
Then, the area of the rectangle is given by:
Step 2: Given Information about the Parallelogram's Area
We know the area of parallelogram is three-fifths the area of rectangle :
Step 3: Relationship between and
It is given that is 25% less than . So, if , then: Since (the height of the rectangle), we can say: or equivalently,
Step 4: Perimeters of Rectangle and Parallelogram
The perimeter of the rectangle is:
To find the perimeter of the parallelogram , note that opposite sides of a parallelogram are equal. The two pairs of opposite sides are and , and and . Since is inscribed in , the lengths of these sides align with parts of :
- (since lies on ).
- (since lies on ).
Thus, the perimeter of parallelogram is:
Step 5: Percentage Difference in Perimeters
Since both the rectangle and the parallelogram share the same perimeter, the percentage by which the perimeter of is greater than the perimeter of is:
Conclusion
The perimeter of the rectangle is 0% greater than the perimeter of the parallelogram .
Would you like a deeper explanation of any step?
Here are five related questions:
- How does changing the proportion of to affect the area of the parallelogram?
- How would the solution change if the area of the parallelogram were different from three-fifths of the rectangle's area?
- What is the perimeter relationship if the parallelogram were tilted within the rectangle?
- How would the answer change if were a different percentage less than ?
- Can this approach be used for other quadrilaterals within rectangles?
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Math Problem Analysis
Mathematical Concepts
Geometry
Area of Rectangle
Area of Parallelogram
Perimeter of Rectangle
Perimeter of Parallelogram
Proportions
Algebra
Formulas
Area of Rectangle = l * w
Area of Parallelogram = (3/5) * (l * w)
Perimeter of Rectangle = 2 * (l + w)
Perimeter of Parallelogram = 2 * (l + w)
Theorems
Area and Perimeter of Parallelogram
Proportional Relationships
Suitable Grade Level
Grades 9-11