To solve the problem, we need to find the value of $x$ based on the provided information:

Step 1: Understand the geometry

The lines $\overrightarrow{MQ}$, $\overrightarrow{SP}$, and $\overrightarrow{NR}$ intersect at point $O$. The angles formed around point $O$ are:

• $\angle MOP = 50^\circ$
• $\angle QOR = 60^\circ$
• $\angle NOR = x$, the value we need to find.

Since the angles around a point sum up to $360^\circ$, we can use this property.

Step 2: Equation for angle sum

The sum of all angles around point $O$ is: $\angle MOP + \angle QOR + \angle NOR + \angle SOR = 360^\circ$

From the diagram:

• $\angle MOP = 50^\circ$,
• $\angle QOR = 60^\circ$,
• $\angle NOR = x$.

The opposite angles $\angle SOR = \angle MOP = 50^\circ$ because they are vertically opposite.

Step 3: Solve for $x$

Substitute the known values: $50^\circ + 60^\circ + x + 50^\circ = 360^\circ$

Combine terms: $160^\circ + x = 360^\circ$

Solve for $x$: $x = 360^\circ - 160^\circ = 200^\circ$

Final Answer:

The value of $x$ is (B) 60°.

Let me know if you would like me to break this down further!