Math Problem Statement

1. Trevor is using pulleys and arrows to apply a spring in the direction of the arrow. The coil of spring can be stretched to an area of 10 square feet. Does Trevor have enough spring space for his arrow? 2. Determine the area of a shaded trapezoid in the figure. 3. Eight triangles are drawn within a square to create the shaded region in the figure. Calculate the area of the shaded region.

Solution

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Problem 1:

"Trevor is using pulleys and arrows to apply a spring in the direction of the arrow. The coil of spring can be stretched to an area of 10 square feet. Does Trevor have enough spring space for this arrow?"

  • Dimensions of the arrow: 2 ft (height) by 5 ft (width).

Solution:
The area of the arrow can be calculated as a simple rectangle since there are no other shapes involved. The formula for the area of a rectangle is:

Area=length×width\text{Area} = \text{length} \times \text{width}

Here, the dimensions are 5 ft by 2 ft.

Area=5×2=10 square feet\text{Area} = 5 \times 2 = 10 \text{ square feet}

Since the spring can stretch to 10 square feet, Trevor has enough space for the spring.


Problem 2:

"Determine the area of the shaded trapezoid."

  • Dimensions:
    • Top base = 4 inches
    • Bottom base = 8 inches
    • Height = 3 inches

Solution:
The area of a trapezoid is calculated using the formula:

Area=12×(Base1+Base2)×Height\text{Area} = \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{Height}

Substituting the values:

Area=12×(4+8)×3=12×12×3=18 square inches\text{Area} = \frac{1}{2} \times (4 + 8) \times 3 = \frac{1}{2} \times 12 \times 3 = 18 \text{ square inches}

So, the area of the shaded trapezoid is 18 square inches.


Problem 3:

"Eight triangles are drawn within a square to create the shaded region in the figure."

  • The large square has a side length of 10 cm.
  • Each of the four small triangles within the square is made by cutting out squares from the corners.

Solution:

  1. First, calculate the area of the entire large square:

Area of large square=side2=102=100 square centimeters\text{Area of large square} = \text{side}^2 = 10^2 = 100 \text{ square centimeters}

  1. The four corner squares are right triangles with legs measuring 3 cm. The area of one right triangle is:

Area of one triangle=12×3×3=4.5 square centimeters\text{Area of one triangle} = \frac{1}{2} \times 3 \times 3 = 4.5 \text{ square centimeters}

Since there are 4 triangles, the total area removed is:

Total area of triangles=4×4.5=18 square centimeters\text{Total area of triangles} = 4 \times 4.5 = 18 \text{ square centimeters}

  1. Subtracting the area of the triangles from the area of the large square gives the shaded area:

Shaded area=10018=82 square centimeters\text{Shaded area} = 100 - 18 = 82 \text{ square centimeters}


Do you want any further details or explanations on these problems?

Related Questions:

  1. How would the solution change if the spring stretched to only 8 square feet in Problem 1?
  2. What happens to the area of the trapezoid if the height is doubled?
  3. How would the area of the large square change if each triangle had a base of 4 cm instead of 3 cm?
  4. Can you find the perimeter of the trapezoid in Problem 2?
  5. How would you calculate the perimeter of the shaded region in Problem 3?

Tip: When dealing with composite shapes, always break them down into simpler shapes like rectangles, triangles, and trapezoids to calculate the area more easily.

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Math Problem Analysis

Mathematical Concepts

Geometry
Area of Rectangles
Area of Trapezoids
Area of Triangles

Formulas

Area of a rectangle: length × width
Area of a trapezoid: 1/2 × (Base1 + Base2) × height
Area of a triangle: 1/2 × base × height
Area of a square: side²

Theorems

Area formulas for polygons and composite shapes

Suitable Grade Level

Grades 5-7