Math Problem Statement

Complete the proof by choosing the correct reason for each step in a geometric proof involving segments PR, SU, PQ, TU, and QR. Given: PR = SU and PQ = TU, Prove: QR = ST.

Solution

The image you uploaded shows a geometric proof where we need to prove that QR=STQR = ST using the given information:

  • PR=SUPR = SU
  • PQ=TUPQ = TU

Let's break down the steps in the proof:

  1. Statement: PR=PQ+QRPR = PQ + QR
    Reason: This comes from the segment addition postulate, which states that the whole segment is the sum of its parts.

  2. Statement: SU=ST+TUSU = ST + TU
    Reason: Similarly, this is from the segment addition postulate applied to segment SUSU.

  3. Statement: PR=SUPR = SU
    Reason: This is given in the problem.

  4. Statement: PQ+QR=ST+TUPQ + QR = ST + TU
    Reason: Substitution. Since PR=SUPR = SU from the given information, we can substitute PRPR and SUSU into the equations derived from the segment addition postulate.

  5. Statement: PQ=TUPQ = TU
    Reason: This is also given in the problem.

  6. Statement: TU+QR=ST+TUTU + QR = ST + TU
    Reason: Substitution. From the previous steps, we substitute PQ=TUPQ = TU into the equation.

  7. Statement: QR=STQR = ST
    Reason: Subtraction property of equality. After subtracting TUTU from both sides, we arrive at the final result, QR=STQR = ST.

Here's a completed version of the table:

StatementReason
1. PR=PQ+QRPR = PQ + QRSegment Addition Postulate
2. SU=ST+TUSU = ST + TUSegment Addition Postulate
3. PR=SUPR = SUGiven
4. PQ+QR=ST+TUPQ + QR = ST + TUSubstitution
5. PQ=TUPQ = TUGiven
6. TU+QR=ST+TUTU + QR = ST + TUSubstitution
7. QR=STQR = STSubtraction Property of Equality

Would you like more details or have any further questions?


Here are 5 related questions for deeper understanding:

  1. What is the segment addition postulate, and how does it apply in geometry?
  2. How does the substitution property help in geometric proofs?
  3. What is the subtraction property of equality, and why is it important here?
  4. Can you think of another geometric situation where segment addition could be used?
  5. How do properties of equality assist in manipulating equations in proofs?

Tip: In geometry, the key to many proofs lies in recognizing congruent segments or angles and using properties of equality to manipulate these relationships effectively.

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Math Problem Analysis

Mathematical Concepts

Geometry
Segment Addition Postulate
Properties of Equality

Formulas

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Theorems

Segment Addition Postulate
Subtraction Property of Equality
Substitution Property

Suitable Grade Level

Grades 8-10