Math Problem Statement

За растяща геометрична прогресия с общ член an > 0 е известно, че a5 - a1 = 5(a3 - a1). Частното на прогресията е: a) 3/2, b) 2, c) 5/2, d) 3.

Solution

Let's solve the given problem step by step.

Problem Analysis:

We are tasked with finding the common ratio of a geometric progression (геометрична прогресия) where:

  1. an>0a_n > 0, so all terms are positive.
  2. It is given that: a5a1=5(a3a1)a_5 - a_1 = 5 \cdot (a_3 - a_1)

Key formula for a geometric progression:

The general term of a geometric progression can be expressed as: an=a1qn1a_n = a_1 \cdot q^{n-1} where qq is the common ratio.

Express the terms:

  • a1=a1a_1 = a_1
  • a3=a1q2a_3 = a_1 \cdot q^{2}
  • a5=a1q4a_5 = a_1 \cdot q^{4}

Now substitute these into the equation a5a1=5(a3a1)a_5 - a_1 = 5 \cdot (a_3 - a_1): a1q4a1=5(a1q2a1)a_1 \cdot q^4 - a_1 = 5 \cdot \left( a_1 \cdot q^2 - a_1 \right)

Step 1: Factorize a1a_1:

a1(q41)=5a1(q21)a_1 \cdot (q^4 - 1) = 5 \cdot a_1 \cdot (q^2 - 1)

Since a1>0a_1 > 0, we can divide through by a1a_1: q41=5(q21)q^4 - 1 = 5 \cdot (q^2 - 1)

Step 2: Simplify:

Expand both sides: q41=5q25q^4 - 1 = 5q^2 - 5

Rearrange to form a standard equation: q45q2+4=0q^4 - 5q^2 + 4 = 0

Step 3: Substitute x=q2x = q^2:

Let x=q2x = q^2, so the equation becomes: x25x+4=0x^2 - 5x + 4 = 0

Factorize: (x4)(x1)=0(x - 4)(x - 1) = 0

Thus: x=4orx=1x = 4 \quad \text{or} \quad x = 1

Step 4: Solve for qq:

Since x=q2x = q^2, we have: q2=4q=2orq=2q^2 = 4 \quad \Rightarrow \quad q = 2 \quad \text{or} \quad q = -2 q2=1q=1orq=1q^2 = 1 \quad \Rightarrow \quad q = 1 \quad \text{or} \quad q = -1

However, since q>0q > 0 (given that an>0a_n > 0), the only valid solutions are: q=2orq=1q = 2 \quad \text{or} \quad q = 1

Final Step:

For a geometric progression, q=1q = 1 would make all terms the same, which contradicts the setup of the problem. Hence: q=2q = 2

Final Answer:

The common ratio qq is: 2(Answer B)\boxed{2 \, (\text{Answer B})}


Let me know if you'd like detailed clarifications!

Related Questions:

  1. How can we derive the general formula for a geometric progression?
  2. What happens if qq is negative in a geometric sequence?
  3. Can a geometric progression have q=1q = 1? Why or why not?
  4. How do we verify if a sequence is geometric?
  5. What are some real-world examples of geometric progressions?

Tip:

Always simplify equations step by step, especially when working with sequences or progressions!

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Math Problem Analysis

Mathematical Concepts

Geometric Progression
Equations
Factoring

Formulas

General term of a geometric progression: an = a1 * q^(n-1)

Theorems

Properties of geometric progressions
Equations solving techniques

Suitable Grade Level

Grades 9-12