Math Problem Statement

Find the general solution to the equation: \[ \mathbf{x}'(t) = A \mathbf{x}(t), \] where \[ A = \begin{pmatrix} 1 & 1 & 2 \\ 1 & 2 & 1 \\ 2 & 1 & 1 \end{pmatrix}. \]

Solution

To find the general solution to this system of differential equations, we have to solve:

x(t)=Ax(t),\mathbf{x}'(t) = A \mathbf{x}(t),

where A=(112121211).A = \begin{pmatrix} 1 & 1 & 2 \\ 1 & 2 & 1 \\ 2 & 1 & 1 \end{pmatrix}.

The general approach involves the following steps:

Step 1: Find the Eigenvalues of AA

  1. Compute the characteristic polynomial of AA by solving det(AλI)=0\det(A - \lambda I) = 0.
  2. This will provide the eigenvalues λ1\lambda_1, λ2\lambda_2, and λ3\lambda_3.

Step 2: Find the Eigenvectors

  1. For each eigenvalue λi\lambda_i, solve (AλiI)v=0(A - \lambda_i I) \mathbf{v} = 0 to find the corresponding eigenvector vi\mathbf{v}_i.

Step 3: Construct the General Solution

  1. Using the eigenvalues and eigenvectors, the general solution to the system will take the form: x(t)=c1eλ1tv1+c2eλ2tv2+c3eλ3tv3,\mathbf{x}(t) = c_1 e^{\lambda_1 t} \mathbf{v}_1 + c_2 e^{\lambda_2 t} \mathbf{v}_2 + c_3 e^{\lambda_3 t} \mathbf{v}_3, where c1c_1, c2c_2, and c3c_3 are constants determined by initial conditions.

Let me carry out these steps for you.The matrix AA has three distinct eigenvalues and corresponding eigenvectors as follows:

  1. Eigenvalue λ1=1\lambda_1 = -1 with eigenvector v1=(101)\mathbf{v}_1 = \begin{pmatrix} -1 \\ 0 \\ 1 \end{pmatrix}.
  2. Eigenvalue λ2=1\lambda_2 = 1 with eigenvector v2=(121)\mathbf{v}_2 = \begin{pmatrix} 1 \\ -2 \\ 1 \end{pmatrix}.
  3. Eigenvalue λ3=4\lambda_3 = 4 with eigenvector v3=(111)\mathbf{v}_3 = \begin{pmatrix} 1 \\ 1 \\ 1 \end{pmatrix}.

General Solution

The general solution to the system is given by:

x(t)=c1et(101)+c2et(121)+c3e4t(111),\mathbf{x}(t) = c_1 e^{-t} \begin{pmatrix} -1 \\ 0 \\ 1 \end{pmatrix} + c_2 e^{t} \begin{pmatrix} 1 \\ -2 \\ 1 \end{pmatrix} + c_3 e^{4t} \begin{pmatrix} 1 \\ 1 \\ 1 \end{pmatrix},

where c1c_1, c2c_2, and c3c_3 are constants determined by initial conditions.

Would you like further details on any part of this solution?

Here are five related questions you might find helpful:

  1. How do we verify that these eigenvalues and eigenvectors satisfy the original matrix equation?
  2. What if the matrix AA had repeated eigenvalues? How would the solution change?
  3. Can we solve this system if we were given initial conditions?
  4. How does the behavior of the solution change as tt \to \infty?
  5. How would we approach this problem if AA were a non-diagonalizable matrix?

Tip: Understanding how eigenvalues affect the solution’s growth or decay is crucial, especially when analyzing the stability of systems.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Linear Algebra
Differential Equations
Eigenvalues and Eigenvectors

Formulas

General solution for linear differential equation \( \mathbf{x}'(t) = A \mathbf{x}(t) \): \( \mathbf{x}(t) = c_1 e^{\lambda_1 t} \mathbf{v}_1 + c_2 e^{\lambda_2 t} \mathbf{v}_2 + c_3 e^{\lambda_3 t} \mathbf{v}_3 \)
Characteristic polynomial \( \det(A - \lambda I) = 0 \) to find eigenvalues

Theorems

Eigenvalue and Eigenvector Theorem

Suitable Grade Level

University level (Calculus and Linear Algebra)