Math Problem Statement

You deposit $1000 in an account that pays 7% interest compounded semiannually. After 5 years, the interest rate is increased to 7.08% compounded quarterly. Whatwill be the value of the account after a total of 10 years? Round to the nearest dollar as needed.

Solution

To calculate the future value of the account, we need to split the problem into two parts:

  1. First 5 years: The account earns 7% interest compounded semiannually.
  2. Last 5 years: The interest rate changes to 7.08% compounded quarterly.

Step 1: Future Value After 5 Years at 7% Compounded Semiannually

The formula for compound interest is:

A=P(1+rn)ntA = P \left(1 + \frac{r}{n}\right)^{nt}

Where:

  • AA is the future value of the investment/loan, including interest.
  • PP is the principal investment amount ($1000).
  • rr is the annual interest rate (decimal form).
  • nn is the number of times that interest is compounded per year.
  • tt is the time the money is invested for in years.

For the first 5 years:

  • P=1000P = 1000
  • r=0.07r = 0.07 (7%)
  • n=2n = 2 (semiannual compounding)
  • t=5t = 5 years

Now we can calculate the amount after 5 years:

A1=1000(1+0.072)2×5A_1 = 1000 \left(1 + \frac{0.07}{2}\right)^{2 \times 5}

Step 2: Future Value for the Next 5 Years at 7.08% Compounded Quarterly

After 5 years, the interest rate changes to 7.08%, compounded quarterly.

Using the same formula, but this time for the next 5 years:

  • The new principal will be the amount from Step 1 (A1A_1).
  • The interest rate r=0.0708r = 0.0708 (7.08%).
  • n=4n = 4 (quarterly compounding).
  • t=5t = 5 years.

We will calculate the future value based on the amount after the first 5 years.

Let me calculate both steps now.

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Math Problem Analysis

Mathematical Concepts

Compound Interest
Exponential Growth

Formulas

Compound interest formula: A = P(1 + r/n)^(nt)

Theorems

Exponential Growth in Finance

Suitable Grade Level

Grades 10-12