Math Problem Statement

Calculate the future value. (Round your answer to two decimal places.)

P = $26,000, r = 9% compounded monthly, t = 7 years

Solution

To calculate the future value AA of an investment with monthly compounding, we can use the compound interest formula:

A=P(1+rn)ntA = P \left(1 + \frac{r}{n}\right)^{nt}

where:

  • P=26,000P = 26,000 (the principal),
  • r=0.09r = 0.09 (annual interest rate as a decimal),
  • n=12n = 12 (compounded monthly, so 12 times per year),
  • t=7t = 7 (time in years).

Step-by-Step Calculation:

  1. Calculate the monthly interest rate: rn=0.0912=0.0075\frac{r}{n} = \frac{0.09}{12} = 0.0075

  2. Calculate the total number of compounding periods: nt=12×7=84nt = 12 \times 7 = 84

  3. Plug values into the formula: A=26,000(1+0.0075)84A = 26,000 \left(1 + 0.0075\right)^{84}

  4. Calculate the expression inside the parentheses: 1+0.0075=1.00751 + 0.0075 = 1.0075

  5. Raise 1.0075 to the power of 84: 1.0075841.7474220511.0075^{84} \approx 1.747422051

  6. Multiply by the principal: A26,000×1.74742205145,432.97A \approx 26,000 \times 1.747422051 \approx 45,432.97

Final Answer:

A45,432.97A \approx 45,432.97

The future value of the investment is approximately $45,432.97.

Would you like more details, or do you have any questions?


Here are 5 related questions to explore further:

  1. What would be the future value if the interest rate increased to 10%?
  2. How does changing the compounding frequency to quarterly affect the future value?
  3. What is the effective annual rate (EAR) for a 9% nominal rate compounded monthly?
  4. How much total interest is earned over the 7 years?
  5. How does a change in the investment period, say to 10 years, affect the future value?

Tip: Monthly compounding can yield significantly more than annual compounding due to more frequent application of interest.

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Math Problem Analysis

Mathematical Concepts

Compound Interest
Exponential Growth

Formulas

Compound Interest Formula: A = P(1 + r/n)^(nt)

Theorems

Compound Interest Theorem

Suitable Grade Level

Grades 10-12