To solve this problem, we can use the formula for the future value of an ordinary annuity, since you are making regular, annual deposits:

$A = P \times \frac{(1 + r)^n - 1}{r}$

Where:

• $A$ is the future value of the annuity (the total amount in the account after 35 years),
• $P$ is the annual deposit ($2000),
• $r$ is the annual interest rate (6% or 0.06),
• $n$ is the number of years (35 years).

Let's calculate:

$A = 2000 \times \frac{(1 + 0.06)^{35} - 1}{0.06}$

First, calculate $(1 + 0.06)^{35}$:

$(1 + 0.06)^{35} = 1.06^{35}$

Now, I'll compute the full expression for $A$.The total amount you will have in the account after 35 years is approximately $222,869.56.

Would you like further details or clarifications on this?

Here are 5 related questions you might find interesting:

1. What would happen if the interest rate changed to 8%?
2. How does the future value change if you deposit for 40 years instead of 35?
3. What would be the future value if you deposited $3000 annually?
4. How does the compounding frequency (monthly or quarterly) affect the future value?
5. What is the difference between an ordinary annuity and an annuity due?

Tip: Regular contributions to an account with compound interest significantly increase the future value due to the power of compounding.